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anonymous

  • one year ago

Please answer this math logic question which I will send a picture of.

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    @mitchal

  3. anonymous
    • one year ago
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    B cause as long the equation stays the same on both side it stays true and shwo that negated equation.

  4. anonymous
    • one year ago
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    Wait what...

  5. anonymous
    • one year ago
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    let me work on it again i might have misread it

  6. anonymous
    • one year ago
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    Ok

  7. phi
    • one year ago
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    The want you to prove the statement using "proof by contradiction" Start with the statement \[ 2(10x+3) \ne 5 (4x-3) \] Proof by Contradiction: Assume the statement is false, and that \[ 2(10x+3) = 5 (4x-3) \] now distribute the 2 on the left side and distribute the 5 on the right side 20x + 6= 20x-15 add -20x to both sides what do you get ?

  8. anonymous
    • one year ago
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    Well since you add -20x to each side it zeros out both 20x making it 6=-15?

  9. anonymous
    • one year ago
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    Is that right or am i confused?

  10. anonymous
    • one year ago
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    ohhh i see what i did wrong...i kept screwing up on the c step -_-

  11. phi
    • one year ago
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    yes. and 6 does not equal -15. this is a contradiction. Therefore the assumption we started with that 2(10x+3)=5(4x−3) is not true, and therefore it must be \[ 2(10x+3) \ne5(4x−3)\] and we have proved the statement by contradiction

  12. anonymous
    • one year ago
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    Ok thanks Phi :)

  13. anonymous
    • one year ago
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    You too Mitchal

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