anonymous
  • anonymous
Please answer this math logic question which I will send a picture of.
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
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anonymous
  • anonymous
anonymous
  • anonymous
B cause as long the equation stays the same on both side it stays true and shwo that negated equation.

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anonymous
  • anonymous
Wait what...
anonymous
  • anonymous
let me work on it again i might have misread it
anonymous
  • anonymous
Ok
phi
  • phi
The want you to prove the statement using "proof by contradiction" Start with the statement \[ 2(10x+3) \ne 5 (4x-3) \] Proof by Contradiction: Assume the statement is false, and that \[ 2(10x+3) = 5 (4x-3) \] now distribute the 2 on the left side and distribute the 5 on the right side 20x + 6= 20x-15 add -20x to both sides what do you get ?
anonymous
  • anonymous
Well since you add -20x to each side it zeros out both 20x making it 6=-15?
anonymous
  • anonymous
Is that right or am i confused?
anonymous
  • anonymous
ohhh i see what i did wrong...i kept screwing up on the c step -_-
phi
  • phi
yes. and 6 does not equal -15. this is a contradiction. Therefore the assumption we started with that 2(10x+3)=5(4x−3) is not true, and therefore it must be \[ 2(10x+3) \ne5(4x−3)\] and we have proved the statement by contradiction
anonymous
  • anonymous
Ok thanks Phi :)
anonymous
  • anonymous
You too Mitchal

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