B cause as long the equation stays the same on both side it stays true and shwo that negated equation.
let me work on it again i might have misread it
The want you to prove the statement using "proof by contradiction" Start with the statement \[ 2(10x+3) \ne 5 (4x-3) \] Proof by Contradiction: Assume the statement is false, and that \[ 2(10x+3) = 5 (4x-3) \] now distribute the 2 on the left side and distribute the 5 on the right side 20x + 6= 20x-15 add -20x to both sides what do you get ?
Well since you add -20x to each side it zeros out both 20x making it 6=-15?
Is that right or am i confused?
ohhh i see what i did wrong...i kept screwing up on the c step -_-
yes. and 6 does not equal -15. this is a contradiction. Therefore the assumption we started with that 2(10x+3)=5(4x−3) is not true, and therefore it must be \[ 2(10x+3) \ne5(4x−3)\] and we have proved the statement by contradiction
Ok thanks Phi :)
You too Mitchal