pre-cal please help, pretty simple but just can't think. 1. Solve: 3(x-5) ≤x-9

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pre-cal please help, pretty simple but just can't think. 1. Solve: 3(x-5) ≤x-9

Mathematics
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i think i got it
what is x though
It doesn't say but I know this is what you have to do in one step |dw:1443195793509:dw|

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ok
x = 17?
thats right^^^^
did you get it
No, I know x doesn't equal 17
i suggest use mathway that is all im gonna do
I did but it doesn't show you the work
i cant ether srry tho
3x - 15 <= x - 9 subtract x from both sides 2x - 15 <= -9 now add 15 to both sides then divide both sides by 2
Ah okay, got it. Thanks
yw
Wait, where did you get 15 @welshfella
oh right i distributed 3 over x - 5 3(x - 5) = 3*x + 3*-5) = 3x - 15
|dw:1443197387328:dw|
Right, got it. Thanks again :)
ok

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