anonymous
  • anonymous
4+3i/2-5i
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
triciaal
  • triciaal
do you need to simplify? if so rationalize the denominator means multiply by 1 expressed as the conjugate of the denominator remember that i^2 = -1
triciaal
  • triciaal
|dw:1443197949997:dw|
triciaal
  • triciaal
original in orange, conjugate expressed as 1 in green, what factors to multiply blue

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

triciaal
  • triciaal
|dw:1443198305494:dw| the general format is a + bi
anonymous
  • anonymous
What am I doing wrong?
1 Attachment
misty1212
  • misty1212
Hi!!
misty1212
  • misty1212
too much work for one thing
misty1212
  • misty1212
\[(2-5i)(2+5i)=2^2+5^2=4+25=27\] for your denominator
misty1212
  • misty1212
oops \[4+25=29\] doe
misty1212
  • misty1212
numerator is \[(4+3i)(2+5i)=(4\times 2-3\times 5)+(4\times 5+3\times 2)i\]
anonymous
  • anonymous
It says this is the answer- #2
1 Attachment
misty1212
  • misty1212
i agree
misty1212
  • misty1212
the denomintor is \(27\) and the numerator is \[(4+3i)(2+5i)=(4\times 2-3\times 5)+(4\times 5+3\times 2)i=8-15+(20+6)i=-7+26i\]
misty1212
  • misty1212
oops
triciaal
  • triciaal
|dw:1443199952838:dw|
misty1212
  • misty1212
\[(4+3i)(2+5i)=(4\times 2-3\times 5)+(4\times 5+3\times 2)i\\=8-15+(20+6)i=-7+26i\]
anonymous
  • anonymous
Thank you!
misty1212
  • misty1212
giving you \[\frac{-7+26i}{27}=\frac{-7}{27}+\frac{26}{27}i\]in standard form
triciaal
  • triciaal
always trust my process not my arithmetic , sorry
anonymous
  • anonymous
Lol thank you both!
triciaal
  • triciaal
@misty1212 you too not 27 29
triciaal
  • triciaal
you are welcome
misty1212
  • misty1212
lol i made the same mistake twice !!

Looking for something else?

Not the answer you are looking for? Search for more explanations.