Olyalhic
  • Olyalhic
(will give medal) factor by grouping uy + 3u - 2y - 6
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
(u-2)(y+3)
Olyalhic
  • Olyalhic
can you explain how you did it? (i'm having a major brain fart rn)
misty1212
  • misty1212
HI!!

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misty1212
  • misty1212
it says "factor by grouping" right?
Olyalhic
  • Olyalhic
yes
misty1212
  • misty1212
\[\color{red}{uy + 3u} -\color{blue}{ 2y - 6} \]
misty1212
  • misty1212
common factor of \(u\) in the red part, and \(2\) in the blue part
misty1212
  • misty1212
\[\color{red}{u(y+3)}+\color{blue}{-2(y+3)}\]
misty1212
  • misty1212
now each term has a common factor of \(y+3\) giving you \[(u-2)(y+3)\]
Olyalhic
  • Olyalhic
oh okay thank you that makes a lot more sense @misty1212

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