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Goose.
 one year ago
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For the function f(x) = 3(x − 1)2 + 2, identify the vertex, domain, and range.
The vertex is (1, 2), the domain is all real numbers, and the range is y ≥ 2.
The vertex is (1, 2), the domain is all real numbers, and the range is y ≤ 2.
The vertex is (–1, 2), the domain is all real numbers, and the range is y ≥ 2.
The vertex is (–1, 2), the domain is all real numbers, and the range is y ≤ 2.
Goose.
 one year ago
Help! Will medal and fan! For the function f(x) = 3(x − 1)2 + 2, identify the vertex, domain, and range. The vertex is (1, 2), the domain is all real numbers, and the range is y ≥ 2. The vertex is (1, 2), the domain is all real numbers, and the range is y ≤ 2. The vertex is (–1, 2), the domain is all real numbers, and the range is y ≥ 2. The vertex is (–1, 2), the domain is all real numbers, and the range is y ≤ 2.

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm y=a(xh)^2+k\] is a vertex form of parabola where (h,k) is the vertex domain of parabola would be all real numbers (ALWAYS)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0let's see dw:1443208361022:dw so that's why range would be all real numbers

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0now the range depends on the ycoordinate of the vertex

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[ f(x) = 3(x − 1)^2 + 2\] what is h and k in this equation ?
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