Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide that Jenny gets to choose their lunch order if the flower she randomly picks from the bouquet is a carnation or a rose. What is the probability that Jenny gets to choose lunch? 4/11 7/11 3/11 2/3

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Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide that Jenny gets to choose their lunch order if the flower she randomly picks from the bouquet is a carnation or a rose. What is the probability that Jenny gets to choose lunch? 4/11 7/11 3/11 2/3

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Are these ratios?

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Other answers:

idk thats all the question says
okay well if jenny gets to choose lunch if she chooses a carnation or a rose. How many flowers are either a carnation or a rose?
23?
No.... if their are 4 roses and 3 carnations how many is that together?
my bad they are ratios so 4/11?
No but when you put the carnations and roses together you have 7 flowers that are either carnations or roses correct?
yes
So as you already said when you said 4/11 you were saying that their are 11 flowers in the whole bouquet.
so its 7/11
yes, that's what i would say is correct as long as you can't simplify it and from what i can tell you cant.
thankyou it was right
Your welcome glad I could help

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