## mortonsalt one year ago Hello everyone! I was wondering if anyone can help me with this question? Picture attached.

1. mortonsalt

2. mortonsalt

$\lambda=\frac{hc}{E_{ph}}$ right?

3. mortonsalt

Do I get the difference of eV, e.g. like when n=2 goes to n=1, eV=-13.6-(-3.4)?

4. anonymous

the lowest the electron fall the higher is the energy that release, the higher the energy the lower the wavelength. If an electron fall from any level to the level 1 will release the most energy (lower wavelength), then if it felt from the 6 to the 1 release more energy than if it fell from the 5. And if it felt from the 5 to the 1 release more than if does from the 4 to the 1. Then if an electron fall to the n=2 wherever level is coming from will always release less energy that any other electron falling to the n=1

5. anonymous

4 ->3 4 ->2 2 ->1 3 -> 1

6. mortonsalt

Thank you so much! I understand it now.

7. anonymous

Yes you can replace the values in the formula and calculate the wavelenght

8. mortonsalt

Thank you! @Cuanchi

9. anonymous
10. Jaynator495

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