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mortonsalt
 one year ago
Hello everyone! I was wondering if anyone can help me with this question?
Picture attached.
mortonsalt
 one year ago
Hello everyone! I was wondering if anyone can help me with this question? Picture attached.

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mortonsalt
 one year ago
Best ResponseYou've already chosen the best response.0\[\lambda=\frac{hc}{E_{ph}}\] right?

mortonsalt
 one year ago
Best ResponseYou've already chosen the best response.0Do I get the difference of eV, e.g. like when n=2 goes to n=1, eV=13.6(3.4)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the lowest the electron fall the higher is the energy that release, the higher the energy the lower the wavelength. If an electron fall from any level to the level 1 will release the most energy (lower wavelength), then if it felt from the 6 to the 1 release more energy than if it fell from the 5. And if it felt from the 5 to the 1 release more than if does from the 4 to the 1. Then if an electron fall to the n=2 wherever level is coming from will always release less energy that any other electron falling to the n=1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04 >3 4 >2 2 >1 3 > 1

mortonsalt
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much! I understand it now.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes you can replace the values in the formula and calculate the wavelenght

mortonsalt
 one year ago
Best ResponseYou've already chosen the best response.0Thank you! @Cuanchi

Jaynator495
 one year ago
Best ResponseYou've already chosen the best response.2Welcome To OpenStudy! Here you will find great helpers and friends, a community of students that help students! We hope you enjoy the experience!
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