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mortonsalt

  • one year ago

Hello everyone! I was wondering if anyone can help me with this question? Picture attached.

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  1. mortonsalt
    • one year ago
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  2. mortonsalt
    • one year ago
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    \[\lambda=\frac{hc}{E_{ph}}\] right?

  3. mortonsalt
    • one year ago
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    Do I get the difference of eV, e.g. like when n=2 goes to n=1, eV=-13.6-(-3.4)?

  4. cuanchi
    • one year ago
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    the lowest the electron fall the higher is the energy that release, the higher the energy the lower the wavelength. If an electron fall from any level to the level 1 will release the most energy (lower wavelength), then if it felt from the 6 to the 1 release more energy than if it fell from the 5. And if it felt from the 5 to the 1 release more than if does from the 4 to the 1. Then if an electron fall to the n=2 wherever level is coming from will always release less energy that any other electron falling to the n=1

  5. cuanchi
    • one year ago
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    4 ->3 4 ->2 2 ->1 3 -> 1

  6. mortonsalt
    • one year ago
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    Thank you so much! I understand it now.

  7. cuanchi
    • one year ago
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    Yes you can replace the values in the formula and calculate the wavelenght

  8. mortonsalt
    • one year ago
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    Thank you! @Cuanchi

  9. cuanchi
    • one year ago
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    https://en.wikipedia.org/wiki/Hydrogen_spectral_series

  10. Jaynator495
    • one year ago
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    Welcome To OpenStudy! Here you will find great helpers and friends, a community of students that help students! We hope you enjoy the experience!

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