## haleyelizabeth2017 one year ago Solve the system $$|y| \ge 2$$ and $$|x| \le 1$$ by graphing. Please no direct answers :)

1. jim_thompson5910

hint: $\Large |y| \ge 2 \text{ is the same as } -2 \le y \le 2$

2. haleyelizabeth2017

Oh!

3. haleyelizabeth2017

Thank you for clarifying that!

4. jim_thompson5910

oh sorry, I mixed up the signs I was focusing on x

5. jim_thompson5910

$\Large |x| \le 1 \text{ is the same as } -1 \le x \le 1$

6. jim_thompson5910

Rule: $\Large |x| \le k \text{ is equivalent to } -k \le x \le k$ where k is any positive number

7. haleyelizabeth2017

Ah hah

8. jim_thompson5910

Rule: $\Large |x| \ge k \text{ is equivalent to } x \ge k \text{ or } x \le -k$ where k is any positive number

9. zzr0ck3r

they want you to graph it

10. jim_thompson5910

using that second rule, $\Large |y| \ge 2$ breaks down into $\Large y \ge 2 \text{ or } y \le -2$

11. jim_thompson5910

So you need to graph the following $\Large -2 \le x \le 2, \ y \ge 2, \ y \le -2$

12. haleyelizabeth2017

Okay so the solution is where they intersect/overlap?

13. jim_thompson5910

correct

14. haleyelizabeth2017

15. haleyelizabeth2017

Thank you so very much!

16. jim_thompson5910

looks good so far