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BloomLocke367
 one year ago
A_1=16.2 N @ 48.0° E of N.
A_2=39.6 N @ 27.0° N of W.
A_3=11.2 N @ 4.00° W of N.
I have to do the same thing as the last problem @phi.
BloomLocke367
 one year ago
A_1=16.2 N @ 48.0° E of N. A_2=39.6 N @ 27.0° N of W. A_3=11.2 N @ 4.00° W of N. I have to do the same thing as the last problem @phi.

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sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1are these vectors?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1Yes. I have to find the resultant vector using the component method

phi
 one year ago
Best ResponseYou've already chosen the best response.1do the same as before: change to "standard angles" then you add up M*cos(x) of each vector

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1I dont know how you approach these but i usually draw standard angles on a cartesain

phi
 one year ago
Best ResponseYou've already chosen the best response.1for the x values and M*sin(x) for the y values

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1okay. hang on this may take a bit. Please be patient cx

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1would the first standard angle measure be 42 degrees? I just subtracted the original from 90

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1and 117 for the second one?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1the final is 94?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1now time to add.. one second.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I got Ax=24.026 and Ay=39.991

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1so it will be in the 2nd quadrant, right?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1so \(A= \sqrt{(24.026)^2+(39.991)^2}\)

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1I mean that looks correct but i havent done any of the corresponding math so im assuming your values are correct

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1so I got A=46.65

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1alright so now your looking for the direction via tan^1(y/x)

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1mhm.. and I got 59.003°... I'm not sure in which direction though..

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1we know were in the second quadrant so we add 180

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1oh because right now we're in the 4th?

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1wait is our x value positive and our y value negative?

phi
 one year ago
Best ResponseYou've already chosen the best response.1** Ax=24.026 and Ay=39.991*** yes that is good

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1x is negative and y is positive

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1i thought we were in the 2nd quadrant

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1that is the second quadrant

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1why did you say 4th then lol

phi
 one year ago
Best ResponseYou've already chosen the best response.1sketch the vector dw:1443215354419:dw

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1because 59.003.. don't we want to get in the 2nd quadrant? wouldn't 59.003 make us in the 4th? and we're trying to get to the second?

phi
 one year ago
Best ResponseYou've already chosen the best response.1You can leave off the signs and just use y= 39.991 x= 24.026 and find the marked angle, then looking at the picture, you see you found the angle between the neg xaxis and the vector 180  that angle is the angle you want

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I am so confused now >.<

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1dw:1443215526042:dw given you know where the vector you've drawn is on the cartesian you can find the correct direction

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1why do you disregard the negative sign?

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1in this case our vector is in the 2nd quadrant (generalized)dw:1443215661242:dw

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1alright lets say the our y value in this case was also negative then our angle would be a positive 59 degrees would you then say its in the first quadrant??? no you would have to find the its actually angle in the 3rd quadrant being 180 + 59dw:1443215872610:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.1I never remember the rules to figure out the angle algebraically I draw the triangle, label the distances (but ignore the sign), and find the angle formed by the hypotenuse and xaxis. once I have that angle, I can figure out what the true angle is in terms of 0 to 360

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1>.< this is so confusing. I

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1tan is y/x your angle is going to positive in the 1st and 3rd quadrant and negative in the 2nd and 4th this is why knowing what value to add to the found angle is useful. Or you could do what phi described which is also valid.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I understand that they are negative in the 2nd and 4th.. and positive in the 1st and 3rd.. I guess I just don't understand when to add 180 and when not to and why.. if that makes sense.

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1let me show you something dw:1443216253502:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.1The rules are a pain to memorize. It should be clear if you treat the problem as a triangle. then knowing what quadrant you are in, you can see whether to add 180, etc

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1I agree that conceptually understanding it would prove to make you stronger with these problems in the long run. rather then memorizing the graph

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1like what do you mean? >.< I don't know this is really confusing me. I was never good at trig.. :/

phi
 one year ago
Best ResponseYou've already chosen the best response.1Let's say you have this vector dw:1443216403123:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.1I assume it is obvious how to find theta ?

phi
 one year ago
Best ResponseYou've already chosen the best response.1now this problem dw:1443216475660:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.1if we treat the x and y as positive distances, then it is the same problem as in the first quadrant. You find theta the same way. but we want this angle dw:1443216568948:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.1Do you see if you know theta, you can find the angle to the vector starting from the positive xaxis ? i.e. find 180  theta

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1ohhhh I think I understand

phi
 one year ago
Best ResponseYou've already chosen the best response.1now this problem dw:1443216774766:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.1You should practice on the problems you just did (where you know the answer) just in case ...

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I can't use the draw tool.. my mouse thing goes BEHIND google chrome.. I don't know why :/

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1could try alt+tabbing and tabbing back in has fixed it for me before

phi
 one year ago
Best ResponseYou've already chosen the best response.1Notice, if you keep the signs on the x and y values, the tan returns negative angles in some of the quadrants, and that is confusing. It is simpler to always work with positive x and y values and find a positive theta. Then, knowing which quadrant the vector is in, you can find the angle using that positive theta

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{#0cbb34}{\text{Originally Posted by}}\) @sweetburger could try alt+tabbing and tabbing back in has fixed it for me before \(\color{#0cbb34}{\text{End of Quote}}\) nope :/ it didn't work.

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1I guess the only thing would to be force close your browser and then open it but wait till your done with the question.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1ohhh see that makes sense Phi.. I finally get why you said to ignore the sign XD

phi
 one year ago
Best ResponseYou've already chosen the best response.1Of course, if you are writing a computer program, you have to work out the rules. (No pictures allowed)

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1phi are you computer software engineer?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{#0cbb34}{\text{Originally Posted by}}\) @phi Of course, if you are writing a computer program, you have to work out the rules. (No pictures allowed) \(\color{#0cbb34}{\text{End of Quote}}\) I'm just in AP Physics cx but good to know :D

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1im in ap physics b too gl with your course

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1thanks :D so is this 59.003° S of W?... or is that completely wrong? >.<

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1south of west would be 3rd quadrant

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1yes I know.. wait.. nevermind O.O I did a bad.. XD I used the original vectors and my teacher said to not do that XD

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1OH IT'S N OF W, RIGHT?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1sorry for the caps, kinda had an explosion of understanding XD

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1yea its great moment when stuff makes sense :P

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1okay now I have a word problem.. can I tag you in a new question?
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