BloomLocke367
  • BloomLocke367
In the Coral Sea the East Australian Current flows 0.9m/s 22.0° West of South. A sea turtle riding the current, dude, swims due East at 2.58m/s. A fish desperate to find his son, Nemo, is moving across the turtles back at 0.25m/s at 35.0° South of East. a. What is the turtle's velocity? b. What is the fish's velocity? c. How many stripes does the fish have? ^^that is a legitimate question on my homework XD
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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BloomLocke367
  • BloomLocke367
@sweetburger
sweetburger
  • sweetburger
might have to google a picture of nemo's dad for c lol
BloomLocke367
  • BloomLocke367
ye cx

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More answers

Jacob902
  • Jacob902
c
BloomLocke367
  • BloomLocke367
I think c is a trick question XD he didn't specify which color stripes lol anyhoo, can you help me with the actual problems? cx
sweetburger
  • sweetburger
This is how i drew my graph may not be correct because currents confuse me sometimes. |dw:1443218314286:dw| this is kinda just for reference I think we just need to go ahead and find the x and y values for each vector and add them up.
BloomLocke367
  • BloomLocke367
how'd you draw the vectors?
BloomLocke367
  • BloomLocke367
wait
BloomLocke367
  • BloomLocke367
I see now lol
BloomLocke367
  • BloomLocke367
so now I break them up into components like normal?
sweetburger
  • sweetburger
so ill make my lists |dw:1443218569870:dw|
sweetburger
  • sweetburger
yes break into components
sweetburger
  • sweetburger
grabbing calc brb
BloomLocke367
  • BloomLocke367
so the first set is the current, the second is the turtle, and the last is the fish?
sweetburger
  • sweetburger
yes
BloomLocke367
  • BloomLocke367
wait.. why did you subtract 22 from 270?
BloomLocke367
  • BloomLocke367
wait.. nevermind cx I keep going back to the reference drawing and answering my own question XD
BloomLocke367
  • BloomLocke367
woe woe woe.. why is the second one 360?
BloomLocke367
  • BloomLocke367
(I checked the graph already too lol)
sweetburger
  • sweetburger
|dw:1443218818993:dw|
sweetburger
  • sweetburger
alright so considering its right on the x axis pointing to positive infinity you could say either cos(0) or cos(360)
BloomLocke367
  • BloomLocke367
why isn't it 180?..
sweetburger
  • sweetburger
and for the y values it would be the same value for sin(0) sin(360)
sweetburger
  • sweetburger
180 is on the x axis pointing towards negative infinity
sweetburger
  • sweetburger
all your x values turn negative and you y values stay 0 when the angle is 180
BloomLocke367
  • BloomLocke367
I don't know why this is so confusing for me :/ thanks for being patient.. but I don't understand
sweetburger
  • sweetburger
ill try to explain it
BloomLocke367
  • BloomLocke367
I'll be right back.. dinner is ready so I'm about to grab me some and I'll come back.
sweetburger
  • sweetburger
|dw:1443219370172:dw|
sweetburger
  • sweetburger
the angles i showed above will give you the same exact value lets use something from the question above .25m/s cos (335) = .227 if you say .25m/s cos(695) it also equals .227 the 695 came from (360+335)
BloomLocke367
  • BloomLocke367
back cx
BloomLocke367
  • BloomLocke367
oh okay I get it. the diagram helped XD
BloomLocke367
  • BloomLocke367
like how it is in the unit circle
sweetburger
  • sweetburger
alright so now to find the angle |dw:1443219938255:dw|
sweetburger
  • sweetburger
yes exactly!
BloomLocke367
  • BloomLocke367
270-22 is 248, right? XD sorry, did it in my head. I just want to be sure
sweetburger
  • sweetburger
|dw:1443220007377:dw|
sweetburger
  • sweetburger
yes u did the math right lol
BloomLocke367
  • BloomLocke367
woe you're going to fast O.O give me time to catch up lol I'm slow XD
sweetburger
  • sweetburger
my bad just let me know if you have any confusions
sweetburger
  • sweetburger
wait im not sure i even needed to solve what i solved. the question isnt asking for this stuff *facepalm*
BloomLocke367
  • BloomLocke367
O.O so what do I do?
sweetburger
  • sweetburger
i think this was a simpler 2 part problem in which we subtract the current vector from the speed vector the for the turtle to find the speed of the turtle
BloomLocke367
  • BloomLocke367
I have to go :O thanks for the help.. I may come back tomorrow to ask for more help XD
sweetburger
  • sweetburger
then using the found speed of the turlte combine the vector of the fish
sweetburger
  • sweetburger
alright im sorry :/
BloomLocke367
  • BloomLocke367
it's okay XD I'm going to the football game. Thank you! you still have helped me understand a lot. talk to ya later!!
sweetburger
  • sweetburger
alright take care
BloomLocke367
  • BloomLocke367
@sweetburger sorry I haven't been on. Can you help me now?

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