In the Coral Sea the East Australian Current flows 0.9m/s 22.0° West of South. A sea turtle riding the current, dude, swims due East at 2.58m/s. A fish desperate to find his son, Nemo, is moving across the turtles back at 0.25m/s at 35.0° South of East.
a. What is the turtle's velocity?
b. What is the fish's velocity?
c. How many stripes does the fish have?
^^that is a legitimate question on my homework XD

- BloomLocke367

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- BloomLocke367

@sweetburger

- sweetburger

might have to google a picture of nemo's dad for c lol

- BloomLocke367

ye cx

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## More answers

- Jacob902

c

- BloomLocke367

I think c is a trick question XD he didn't specify which color stripes lol
anyhoo, can you help me with the actual problems? cx

- sweetburger

This is how i drew my graph may not be correct because currents confuse me sometimes. |dw:1443218314286:dw| this is kinda just for reference I think we just need to go ahead and find the x and y values for each vector and add them up.

- BloomLocke367

how'd you draw the vectors?

- BloomLocke367

wait

- BloomLocke367

I see now lol

- BloomLocke367

so now I break them up into components like normal?

- sweetburger

so ill make my lists |dw:1443218569870:dw|

- sweetburger

yes break into components

- sweetburger

grabbing calc brb

- BloomLocke367

so the first set is the current, the second is the turtle, and the last is the fish?

- sweetburger

yes

- BloomLocke367

wait.. why did you subtract 22 from 270?

- BloomLocke367

wait.. nevermind cx I keep going back to the reference drawing and answering my own question XD

- BloomLocke367

woe woe woe.. why is the second one 360?

- BloomLocke367

(I checked the graph already too lol)

- sweetburger

|dw:1443218818993:dw|

- sweetburger

alright so considering its right on the x axis pointing to positive infinity you could say either cos(0) or cos(360)

- BloomLocke367

why isn't it 180?..

- sweetburger

and for the y values it would be the same value for sin(0) sin(360)

- sweetburger

180 is on the x axis pointing towards negative infinity

- sweetburger

all your x values turn negative and you y values stay 0 when the angle is 180

- BloomLocke367

I don't know why this is so confusing for me :/ thanks for being patient.. but I don't understand

- sweetburger

ill try to explain it

- BloomLocke367

I'll be right back.. dinner is ready so I'm about to grab me some and I'll come back.

- sweetburger

|dw:1443219370172:dw|

- sweetburger

the angles i showed above will give you the same exact value lets use something from the question above .25m/s cos (335) = .227 if you say .25m/s cos(695) it also equals .227 the 695 came from (360+335)

- BloomLocke367

back cx

- BloomLocke367

oh okay I get it. the diagram helped XD

- BloomLocke367

like how it is in the unit circle

- sweetburger

alright so now to find the angle |dw:1443219938255:dw|

- sweetburger

yes exactly!

- BloomLocke367

270-22 is 248, right? XD sorry, did it in my head. I just want to be sure

- sweetburger

|dw:1443220007377:dw|

- sweetburger

yes u did the math right lol

- BloomLocke367

woe you're going to fast O.O give me time to catch up lol
I'm slow XD

- sweetburger

my bad just let me know if you have any confusions

- sweetburger

wait im not sure i even needed to solve what i solved. the question isnt asking for this stuff *facepalm*

- BloomLocke367

O.O so what do I do?

- sweetburger

i think this was a simpler 2 part problem in which we subtract the current vector from the speed vector the for the turtle to find the speed of the turtle

- BloomLocke367

I have to go :O thanks for the help.. I may come back tomorrow to ask for more help XD

- sweetburger

then using the found speed of the turlte combine the vector of the fish

- sweetburger

alright im sorry :/

- BloomLocke367

it's okay XD I'm going to the football game. Thank you! you still have helped me understand a lot. talk to ya later!!

- sweetburger

alright take care

- BloomLocke367

@sweetburger sorry I haven't been on. Can you help me now?

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