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anonymous

  • one year ago

let g(x)=|cos x-1|. the maximum value attained by g on the closed interval [0,2pi] occurs at x equal to: a. -1 b. 0 c. pi/2 d. 2 e. pi

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  1. welshfella
    • one year ago
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    what is the range of cos x?

  2. anonymous
    • one year ago
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    0,2?

  3. welshfella
    • one year ago
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    no, cos 0 and cos 2pi = 1 , cos pi = -1

  4. welshfella
    • one year ago
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    remember the vertical lines mean the absolute value which is positive

  5. anonymous
    • one year ago
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    so -1

  6. anonymous
    • one year ago
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    wait could it be zero 1-1

  7. welshfella
    • one year ago
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    no

  8. welshfella
    • one year ago
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    try putting values of cos x into the expression until you get maximimum value of g

  9. anonymous
    • one year ago
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    2

  10. welshfella
    • one year ago
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    |-1-1| = |-2| = 2 Thats the maximum value of g what value of x will give that?

  11. welshfella
    • one year ago
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    cos x must equal - 1 right? so x = ?

  12. anonymous
    • one year ago
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    -1

  13. welshfella
    • one year ago
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    no cos x = -1 what value of x , in radians, will give cos x = -1?

  14. welshfella
    • one year ago
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    the question asks for value of x , not cos x.

  15. anonymous
    • one year ago
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    0

  16. welshfella
    • one year ago
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    look at my second post

  17. anonymous
    • one year ago
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    1

  18. welshfella
    • one year ago
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    no

  19. anonymous
    • one year ago
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    pi

  20. welshfella
    • one year ago
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    the cos of what angle is -1? check it out with ur calculator

  21. welshfella
    • one year ago
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    yes its pi because cos pi = -1

  22. welshfella
    • one year ago
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    do you follow it now?

  23. anonymous
    • one year ago
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    yes i do thanks:)

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