anonymous
  • anonymous
let g(x)=|cos x-1|. the maximum value attained by g on the closed interval [0,2pi] occurs at x equal to: a. -1 b. 0 c. pi/2 d. 2 e. pi
Mathematics
chestercat
  • chestercat
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welshfella
  • welshfella
what is the range of cos x?
anonymous
  • anonymous
0,2?
welshfella
  • welshfella
no, cos 0 and cos 2pi = 1 , cos pi = -1

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welshfella
  • welshfella
remember the vertical lines mean the absolute value which is positive
anonymous
  • anonymous
so -1
anonymous
  • anonymous
wait could it be zero 1-1
welshfella
  • welshfella
no
welshfella
  • welshfella
try putting values of cos x into the expression until you get maximimum value of g
anonymous
  • anonymous
2
welshfella
  • welshfella
|-1-1| = |-2| = 2 Thats the maximum value of g what value of x will give that?
welshfella
  • welshfella
cos x must equal - 1 right? so x = ?
anonymous
  • anonymous
-1
welshfella
  • welshfella
no cos x = -1 what value of x , in radians, will give cos x = -1?
welshfella
  • welshfella
the question asks for value of x , not cos x.
anonymous
  • anonymous
0
welshfella
  • welshfella
look at my second post
anonymous
  • anonymous
1
welshfella
  • welshfella
no
anonymous
  • anonymous
pi
welshfella
  • welshfella
the cos of what angle is -1? check it out with ur calculator
welshfella
  • welshfella
yes its pi because cos pi = -1
welshfella
  • welshfella
do you follow it now?
anonymous
  • anonymous
yes i do thanks:)

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