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anonymous

  • one year ago

Helmp e set it up please Roger heads east on interstate 80 from Omaha,Nebraska on his motorcycle at the same time that Laura leaves Joliet,Illinois heading west on the same freeway in her restored Model A Car. four hours later they meet at a rest stop outside of davenport,Iowa. if Roger's average speed was twice Laura's average speed and the distance between Omaha and Joliet is 450 miles what was Roger's average speed?

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  1. Defiance
    • one year ago
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    First, fine the time and distance. Time = 4 hours Distance = 'y' Using Distance over time, we know we know he traveled 'x' mph If he traveled twice as fast as Laura, then they meet at 3/4'th. Time = 4 hours Distance = 337.5 337.5 divided by 4 = 84.375 mph

  2. Defiance
    • one year ago
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    Faction is 84 3/8

  3. anonymous
    • one year ago
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    @Defiance I'm having a little trouble understanding where you got 337.5 if the distance was 450?

  4. Defiance
    • one year ago
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    337.5 is 3/4th of the distance. If they meet at a reset area. He traveled twice as fast. Then he goes farther then her. Not all the way.

  5. Defiance
    • one year ago
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    The distance from the cities are 450. But 3/4th of it is 337.5

  6. Defiance
    • one year ago
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    ( Sorry for the confusion! )

  7. anonymous
    • one year ago
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    @Defiance Thank you for clarifying and for answering

  8. Defiance
    • one year ago
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    @Sooch Np. :D

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