Helmp e set it up please
Roger heads east on interstate 80 from Omaha,Nebraska on his motorcycle at the same time that Laura leaves Joliet,Illinois heading west on the same freeway in her restored Model A Car. four hours later they meet at a rest stop outside of davenport,Iowa. if Roger's average speed was twice Laura's average speed and the distance between Omaha and Joliet is 450 miles what was Roger's average speed?

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- anonymous

- jamiebookeater

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- Defiance

First, fine the time and distance.
Time = 4 hours
Distance = 'y'
Using Distance over time, we know we know he traveled 'x' mph
If he traveled twice as fast as Laura, then they meet at 3/4'th.
Time = 4 hours
Distance = 337.5
337.5 divided by 4 = 84.375 mph

- Defiance

Faction is 84 3/8

- anonymous

@Defiance I'm having a little trouble understanding where you got 337.5 if the distance was 450?

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- Defiance

337.5 is 3/4th of the distance.
If they meet at a reset area. He traveled twice as fast.
Then he goes farther then her. Not all the way.

- Defiance

The distance from the cities are 450. But 3/4th of it is 337.5

- Defiance

( Sorry for the confusion! )

- anonymous

@Defiance Thank you for clarifying and for answering

- Defiance

@Sooch Np. :D

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