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anonymous
 one year ago
Helmp e set it up please
Roger heads east on interstate 80 from Omaha,Nebraska on his motorcycle at the same time that Laura leaves Joliet,Illinois heading west on the same freeway in her restored Model A Car. four hours later they meet at a rest stop outside of davenport,Iowa. if Roger's average speed was twice Laura's average speed and the distance between Omaha and Joliet is 450 miles what was Roger's average speed?
anonymous
 one year ago
Helmp e set it up please Roger heads east on interstate 80 from Omaha,Nebraska on his motorcycle at the same time that Laura leaves Joliet,Illinois heading west on the same freeway in her restored Model A Car. four hours later they meet at a rest stop outside of davenport,Iowa. if Roger's average speed was twice Laura's average speed and the distance between Omaha and Joliet is 450 miles what was Roger's average speed?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First, fine the time and distance. Time = 4 hours Distance = 'y' Using Distance over time, we know we know he traveled 'x' mph If he traveled twice as fast as Laura, then they meet at 3/4'th. Time = 4 hours Distance = 337.5 337.5 divided by 4 = 84.375 mph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Defiance I'm having a little trouble understanding where you got 337.5 if the distance was 450?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0337.5 is 3/4th of the distance. If they meet at a reset area. He traveled twice as fast. Then he goes farther then her. Not all the way.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The distance from the cities are 450. But 3/4th of it is 337.5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0( Sorry for the confusion! )

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Defiance Thank you for clarifying and for answering
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