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anonymous
 one year ago
how do i find the seconds it'll take
If an object is projected upward from ground level with an initial velocity of 96ft/sec, its height h in feet after t seconds is given by the equation h=16t^2+96t
anonymous
 one year ago
how do i find the seconds it'll take If an object is projected upward from ground level with an initial velocity of 96ft/sec, its height h in feet after t seconds is given by the equation h=16t^2+96t

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Agl202
 one year ago
Best ResponseYou've already chosen the best response.3Question not finished...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Agl202 That's the whole problem on my worksheet and it then asks "After how many seconds does the object hit the ground?"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When it hits the ground, the height is \(\color{olive}{0}\). \( \color{blue}{h}=16t^2+96t \) \( \color{blue}{0}=16t^2+96t \) \(\tt{solve}~{for}~{\color{red}{ t.}}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i factor out 16t+96?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes. (Sooch I also typed a reply on your other question. )

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay thank you @mathway

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\huge 16(t6)=0\)
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