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open_studier

  • one year ago

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  1. anonymous
    • one year ago
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    ya is correct

  2. jim_thompson5910
    • one year ago
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    they are basically asking you to solve \(3(x+2) - 4=2\)

  3. jim_thompson5910
    • one year ago
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    when you `solve for the inverse function`, you swap x and y, then solve for y so when you plug x = 2 into the inverse, you are really plugging in y = 2 into the original

  4. jim_thompson5910
    • one year ago
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    did you solve \(3(x+2) - 4 = 2\) for x?

  5. jim_thompson5910
    • one year ago
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    Let's check your answer 3(x+2) - 4 = 2 3(8+2) - 4 = 2 ... replace x with 8 3(10) - 4 = 2 30 - 4 = 2 26 = 2 ... this equation is false, so x = 8 is not the solution

  6. jim_thompson5910
    • one year ago
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    scroll back up. I explain how you actually replace y with 2

  7. jim_thompson5910
    • one year ago
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    f(x) = 3(x+2) - 4 is the same as y = 3(x+2) - 4

  8. jim_thompson5910
    • one year ago
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    y = f(x)

  9. anonymous
    • one year ago
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    I think is y=mx-b

  10. jim_thompson5910
    • one year ago
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    yep x = 0 makes 2 = 3(x+2) - 4 true

  11. jim_thompson5910
    • one year ago
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    no problem

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