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x3_drummerchick
 one year ago
How do i solve this!? Will give medals!
Radium221 has a halflife of 30 sec. How long will it take for 84% of a sample to decay? (Round your answer to the nearest whole number.)
x3_drummerchick
 one year ago
How do i solve this!? Will give medals! Radium221 has a halflife of 30 sec. How long will it take for 84% of a sample to decay? (Round your answer to the nearest whole number.)

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dan815
 one year ago
Best ResponseYou've already chosen the best response.3we keep losing 1/2 ever 30 seconds

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1i found the 'r' by doing ln2/30

dan815
 one year ago
Best ResponseYou've already chosen the best response.3wait i have to figure it out too

dan815
 one year ago
Best ResponseYou've already chosen the best response.3then we multiply 30*n to see how many seconds

dan815
 one year ago
Best ResponseYou've already chosen the best response.3okay let me see how to explain this

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1oohhh wait wait i think i know what you mean

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1you start with 1 mg

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1i mean, 1 "sample" of it, right?

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1okay, and howd you get the (1/2)?

dan815
 one year ago
Best ResponseYou've already chosen the best response.3okay so forget like the 30 secs to begin with i mean remember it but we really wanna see how many half lives have passed we just know 1 half live is 30 seconds keep that in mind

dan815
 one year ago
Best ResponseYou've already chosen the best response.3basically like this, now you know that for every half life we multiply by a 1/2

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1okay that makes sense

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1so how would we incorporate that into the formula?

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1dw:1443225321392:dw

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1dw:1443225534573:dw

dan815
 one year ago
Best ResponseYou've already chosen the best response.3every 30 secs u want a new half lige so

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1here is an example layout, but doesnr have answers, it confused me

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1i dont know if that helps any

dan815
 one year ago
Best ResponseYou've already chosen the best response.3gimme a few mins, i am dealing with someone here

dan815
 one year ago
Best ResponseYou've already chosen the best response.3yeah dont worry ill help u understand this stuff its pretty simple

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1actually i think i figured it out!

dan815
 one year ago
Best ResponseYou've already chosen the best response.3i want to show u something important first

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1crap, nvm i got it wrong

dan815
 one year ago
Best ResponseYou've already chosen the best response.3okay remember the (1/2)^n formula

dan815
 one year ago
Best ResponseYou've already chosen the best response.3now lets tweak that a little bit okay we know that for evert 30 secs we want it to be halved so

dan815
 one year ago
Best ResponseYou've already chosen the best response.3now u see every 30 secs we would exactly half it

dan815
 one year ago
Best ResponseYou've already chosen the best response.3the equation they give u is this just in disguise

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1that makes sense

dan815
 one year ago
Best ResponseYou've already chosen the best response.3if we apply e^ln(x) = x e and ln cancel out right

dan815
 one year ago
Best ResponseYou've already chosen the best response.3lets apply to that equation we know has to be right

dan815
 one year ago
Best ResponseYou've already chosen the best response.3do you know your ln rules like ln(x^3)= 3 ln x the power multiples

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1oh wait, dont you bring it to the rfont of the ln?

dan815
 one year ago
Best ResponseYou've already chosen the best response.3with a little bit of manipulation we see that the equation is exactly reuivalent

dan815
 one year ago
Best ResponseYou've already chosen the best response.3there is only 1 rule im applying here over and over

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1yes i do remember those

dan815
 one year ago
Best ResponseYou've already chosen the best response.3okay go ahead fill it all in now

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1dw:1443226609625:dw

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1i got 79.33, is that right?

dan815
 one year ago
Best ResponseYou've already chosen the best response.3i am not using a calculator make sure u round it to the 10th

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.1its correct :) thank you again so much, youre awesome!
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