Assume the population of Lakeville is increasing at a rate of 9% per year If the population of Lakeville is 8,000 today, what will the population be in 3 years?

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Assume the population of Lakeville is increasing at a rate of 9% per year If the population of Lakeville is 8,000 today, what will the population be in 3 years?

Mathematics
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if it increases 9% per year, that means it would increase by 27% in the forthcoming years. So, you do the math. 27% of 8000 is?
the increase is compounded, the second increase will be 109% of 109% of the original population
new value = (start value)*(rate of change)^(periods)

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Other answers:

exponential function
\[P _{n} = P _{initial}*r^n\] the initial population is 4000 n is the year number from the start n = 1,2,3,4... r is the rate of change, here it is 1.09, 9%increase
5832?
In n years, the population will be \[P _{n} = 8000*(1.09)^n\]
10360
yeah, see each increase in year you tack on another multiple of 1.09
3rd year 8000(1.09)(1.09)(1.09)

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