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anonymous
 one year ago
Assume the population of Lakeville is increasing at a rate of 9% per year
If the population of Lakeville is 8,000 today, what will the population be in 3 years?
anonymous
 one year ago
Assume the population of Lakeville is increasing at a rate of 9% per year If the population of Lakeville is 8,000 today, what will the population be in 3 years?

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thadyoung
 one year ago
Best ResponseYou've already chosen the best response.0if it increases 9% per year, that means it would increase by 27% in the forthcoming years. So, you do the math. 27% of 8000 is?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0the increase is compounded, the second increase will be 109% of 109% of the original population

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0new value = (start value)*(rate of change)^(periods)

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0\[P _{n} = P _{initial}*r^n\] the initial population is 4000 n is the year number from the start n = 1,2,3,4... r is the rate of change, here it is 1.09, 9%increase

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0In n years, the population will be \[P _{n} = 8000*(1.09)^n\]

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0yeah, see each increase in year you tack on another multiple of 1.09

DanJS
 one year ago
Best ResponseYou've already chosen the best response.03rd year 8000(1.09)(1.09)(1.09)
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