anonymous
  • anonymous
What is the compound inequality 8 < or = to 2x-4 < 2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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DanJS
  • DanJS
hmm
anonymous
  • anonymous
Hmm what?
DanJS
  • DanJS
\[8 \le (2x-4) \lt 2\] that right?

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More answers

anonymous
  • anonymous
Yes
DanJS
  • DanJS
that is a compound inequality
DanJS
  • DanJS
a
anonymous
  • anonymous
Except there is no parentheses
anonymous
  • anonymous
Ya but i have to find the solution to it
DanJS
  • DanJS
so you have 8 is less than or equal to 2x-4 AND 2x-4 is less than 2
DanJS
  • DanJS
oh, do you want to just isolate x to get the values for x, solve it
anonymous
  • anonymous
My options are: 1. -6 < or = to X < -4 2. -2 < or = to X < -1 3. 0 < or = to X < 5 4. -2 < or = to X < 3
DanJS
  • DanJS
\[8 \le (2x-4) \lt 2\] \[8 +4\le (2x) \lt 2 + 4\] \[\frac{ 12 }{ 2 } \le x \lt \frac{ 6 }{ 2 }\] this says \[6 \le x \lt 3\] which is not true, x can not be bigger than 6 AND less than 3 at the same time
DanJS
  • DanJS
It ca be either OR
DanJS
  • DanJS
you mistyped something in the prob i think
anonymous
  • anonymous
I'm confused
DanJS
  • DanJS
the way you put the problem, you cant have solutions for that, you can break it up into \[x \ge 6~~~~OR~~~~x \lt 3\]
DanJS
  • DanJS
a value can't be both those at the same time,
anonymous
  • anonymous
I just put it the way that the school has it
DanJS
  • DanJS
you missing a negative sign, or something,
DanJS
  • DanJS
put the question down again using the draw tool
DanJS
  • DanJS
the inequality part
anonymous
  • anonymous
|dw:1443228817681:dw|
anonymous
  • anonymous
Is that what you mean @DanJS ?
anonymous
  • anonymous
i say its 1
anonymous
  • anonymous
can you explain why? I am so confused
anonymous
  • anonymous
was it really \[-8 \le x-4\lt 2\]
anonymous
  • anonymous
or \[-8 \le2 x-4\lt 2\]
anonymous
  • anonymous
the second one
anonymous
  • anonymous
add 4 all the way across\[-4\leq 2x<6\] then divide all by 2
anonymous
  • anonymous
so it is \[-2lex <3\]
anonymous
  • anonymous
yeah
anonymous
  • anonymous
\[-2 \le x < 3\]
anonymous
  • anonymous
\[-2\leq x<3\]
anonymous
  • anonymous
Thank you so much!

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