What is the compound inequality 8 < or = to 2x-4 < 2

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

What is the compound inequality 8 < or = to 2x-4 < 2

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

hmm
Hmm what?
\[8 \le (2x-4) \lt 2\] that right?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Yes
that is a compound inequality
a
Except there is no parentheses
Ya but i have to find the solution to it
so you have 8 is less than or equal to 2x-4 AND 2x-4 is less than 2
oh, do you want to just isolate x to get the values for x, solve it
My options are: 1. -6 < or = to X < -4 2. -2 < or = to X < -1 3. 0 < or = to X < 5 4. -2 < or = to X < 3
\[8 \le (2x-4) \lt 2\] \[8 +4\le (2x) \lt 2 + 4\] \[\frac{ 12 }{ 2 } \le x \lt \frac{ 6 }{ 2 }\] this says \[6 \le x \lt 3\] which is not true, x can not be bigger than 6 AND less than 3 at the same time
It ca be either OR
you mistyped something in the prob i think
I'm confused
the way you put the problem, you cant have solutions for that, you can break it up into \[x \ge 6~~~~OR~~~~x \lt 3\]
a value can't be both those at the same time,
I just put it the way that the school has it
you missing a negative sign, or something,
put the question down again using the draw tool
the inequality part
|dw:1443228817681:dw|
Is that what you mean @DanJS ?
i say its 1
can you explain why? I am so confused
was it really \[-8 \le x-4\lt 2\]
or \[-8 \le2 x-4\lt 2\]
the second one
add 4 all the way across\[-4\leq 2x<6\] then divide all by 2
so it is \[-2lex <3\]
yeah
\[-2 \le x < 3\]
\[-2\leq x<3\]
Thank you so much!

Not the answer you are looking for?

Search for more explanations.

Ask your own question