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anonymous

  • one year ago

identify the transformation of f(x) that each function represents 1. g(x) = f(x - 5) 2. g(x) = 3f(x)

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  1. anonymous
    • one year ago
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    and can you show me the work so i can learn this

  2. jim_thompson5910
    • one year ago
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    In general, if you replace x with x-h, you are shifting the entire graph of f(x) `h` units to the left. That is if h is positive if h is negative, then you go the same number of units but to the right

  3. anonymous
    • one year ago
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    i don't have h do you mean g?

  4. jim_thompson5910
    • one year ago
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    notice how f(x-5) and f(x-h) match up

  5. anonymous
    • one year ago
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    because your replacing 5 with h?

  6. jim_thompson5910
    • one year ago
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    yeah so in your specific case, h = 5 so when we go from f(x) to f(x-5) we shift all of f(x) 5 units to the right. Sorry I mixed up the order above. I mixed up left and right, my bad

  7. jim_thompson5910
    • one year ago
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    h is positive, you shift right h is negative, you shift left

  8. anonymous
    • one year ago
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    oh okay so thats all i write?

  9. anonymous
    • one year ago
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    and for the second one what dould it be since it's multiplication

  10. jim_thompson5910
    • one year ago
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    `oh okay so thats all i write?` yeah all you need to say really is that the entire graph shifts 5 units to the right

  11. jim_thompson5910
    • one year ago
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    that 3 out front means every y coordinate gets tripled visually what that does is vertically stretch the graph by a factor of 3. it's basically 3 times taller than it was before

  12. jim_thompson5910
    • one year ago
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    example: say we know the point (2,5) is on f(x) we know for a fact that (2,15) is on g(x) because 3*f(2) = 3*5 = 15

  13. jim_thompson5910
    • one year ago
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    imagine that happens with every point on f(x)

  14. anonymous
    • one year ago
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    oh ok

  15. anonymous
    • one year ago
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    i have more do you mind helping me i've missed school cause i got really sick and this is make up work but i never learnt this

  16. jim_thompson5910
    • one year ago
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    I'll help with 2 more

  17. anonymous
    • one year ago
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    i have a whole bunch thought...

  18. anonymous
    • one year ago
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    do you mind if we schedule a time tomorrow so you can help me?

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