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anonymous

  • one year ago

9|9-8x|=2x+3 Please explain the steps to completing. I will medal and fan!

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  1. anonymous
    • one year ago
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    @satellite73

  2. anonymous
    • one year ago
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    you have to solve two equations i think

  3. anonymous
    • one year ago
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    for \(x>\frac{9}{8}\) this is the same as \[9(9-8x)=2x+3\]

  4. anonymous
    • one year ago
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    oh maybe i just screwed that up lets make it easiery

  5. anonymous
    • one year ago
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    \[|9-8x|=|8x-9|\] so we can start with \[9|8x-9|=2x+3\]

  6. anonymous
    • one year ago
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    now if \(x>\frac{9}{8}\) that is the same as \[9(8x-9)=2x+3\] which i guess you can solve

  7. anonymous
    • one year ago
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    it is ugly, but you should get \(x=\frac{6}{5}\) i think

  8. anonymous
    • one year ago
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    I'm still confused

  9. anonymous
    • one year ago
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    lets back up and go slow

  10. anonymous
    • one year ago
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    is this line \[|9-8x|=|8x-9|\] clear?

  11. anonymous
    • one year ago
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    yes

  12. anonymous
    • one year ago
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    ok now \(|8x-9|\) is one of two things if \(x> \frac{9}{8}\) then \(8x-9>0\) and if \(8x-9>0\) then \(|8x-9|=8x-9\) because it is positive

  13. anonymous
    • one year ago
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    clear or not ?

  14. anonymous
    • one year ago
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    clear

  15. anonymous
    • one year ago
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    so if \(x>\frac{9}{8}\) you can go ahead and solve \[9(8x-9)=2x+3\]

  16. anonymous
    • one year ago
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    that takes a bit of algebra, but i assume it is doable

  17. anonymous
    • one year ago
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    if not, let me know

  18. anonymous
    • one year ago
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    I don't know how to solve it @satellite73

  19. anonymous
    • one year ago
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    multiply out and get \[72x-81=2x+3\]

  20. anonymous
    • one year ago
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    Do i combine like terms now?

  21. anonymous
    • one year ago
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    subtract \(2x\) get \[70x-81=3\] then add \(81\) to get \[70x=84\] and finally divide by \(70\) to get \[x=\frac{84}{70}=\frac{6}{5}\]

  22. anonymous
    • one year ago
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    ooooooohhhhh ok thank you so much again!!!!

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spraguer (Moderator)
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