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anonymous
 one year ago
How to factor? 12x^627y^4.
I know to take out the three, but I don't know what to do from there. Any help? Thanks.
anonymous
 one year ago
How to factor? 12x^627y^4. I know to take out the three, but I don't know what to do from there. Any help? Thanks.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0once you take out the 3, you have the difference of two squares

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[3(4x^69y^4)\] the inner piece is like \(a^2b^2=(a+b)(ab)\) with \(a=2x^3, b=3y^2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ah, okay, I didn't know the formula. Thank you.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0May I ask for the formula if it is a^2+b^2, @satellite73 ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0`a^2+b^2` is a sum of squares and can't be factored (assuming 'a' and 'b' have nothing in common)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm working on the problem now, just gimme a minute and we'll see if I got it right. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got 2x^5+3y^2)(2x^43y^2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what @jim_thompson5910 said you can factor the "difference of two squares" but not the "sum of two squares"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 How did you get 2x^3?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the exponent for the \(x\) term should be \(3\) in both cases

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is a good question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i visualized \(4x^6\) as \((2x^3)^2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I thought you just subtract. Since to the squared is to, you'd minus two from 6.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So you divide the exponent?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0satellite73 is using the rule \[\LARGE (x^a)^b = x^{a*b}\] notice how the inner exponent 'a' is being multiplied with the outer exponent b

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0so with 4x^6, satellite73 broke up the 6 into 3*2 and used the rule above

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Does my understanding of it? You divide?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Does that work in general or was I just lucky there?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0well again, notice how 6 factors into 3*2 we want the *2 portion so we can ultimately have something squared so that's why we divide by 2 to figure out that other factor

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0if we had say x^10, we'd break it up like 5*2 how do we find 5? well we can say 10/2 = 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ah, okay, I am working on another problem right now. It would mean so much if you could stay for a bit to see if I got it right. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This may take more for more as me as it involves big numbers. Thanks for your patience.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Finally got the factors. 28 and 28.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just realized I didn't give you the problem. XD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0your answer is correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Actually, according to the calculator, it's squared not cubed. :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh no it isn't the exponent should be 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[16x^4+56x^2+49\] is a "perfect square"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(a+b)^2=a^2+2ab+b^2\] in your case \(a=4x^2,b=7\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you. I'm fine for now, but I may be good. Thanks again for your time! :)
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