How to factor? 12x^6-27y^4.
I know to take out the three, but I don't know what to do from there. Any help? Thanks.

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once you take out the 3, you have the difference of two squares

\[3(4x^6-9y^4)\] the inner piece is like \(a^2-b^2=(a+b)(a-b)\) with \(a=2x^3, b=3y^2\)

Ah, okay, I didn't know the formula. Thank you.

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