Homework help with Factoring? Please? Thank you!! I need to see how to work it out, that way I can actually learn this, draw it out if you can? I will post it below thanks !

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- Bookworm14

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- anonymous

you got my attention!

- anonymous

ok you have choices so it make it easier

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## More answers

- Bookworm14

Hey Satellite! long time no see! I have already used the slide and divide method, but i think im gonna have to use grouping, which i am not very good at

- anonymous

when you multiply out any of those "binomials" the last term, the number, will be what you get when you multiply the two constants together
that has to give you \(-30\)

- anonymous

@AliLnn sure

- anonymous

to it could be A \((2b+5)(2b-6)\) or it could be C \((2b-5)(2b+6)\) because \(-5\times 6=-30\) it can't be the other two

- anonymous

damn typo sorry

- Bookworm14

I have to show my work for this, that is why i needed step by step (possibly drawn out) examples -_- sorry and your fine darlin, take your time haha

- anonymous

\[(2b+5)(5b-6)\] or \[(2b-5)(5b+6)\]

- anonymous

i have no idea what "work" you have to show to do this
you pretty much have to grind it til you find it

- anonymous

you can check which ones of the above give you a "middle term" of \(-13b\)

- anonymous

which will of course be C

- Bookworm14

you know what, im just gonna show my work for working out the answer choices and that should be good enough! lol and thank you, my mind was grinding gears over nothin over here haha

- anonymous

you can guess it will be \((2b+?)(5b+?)\) and then reason that one of those has to be positive, the other negative, since the product is negative

- anonymous

you get a bunch of choices, but since you really only have 4 possible answers, you can check the one that is right
otherwise it is very tedious to go through all the possible combinations

- Bookworm14

Thanks Love! :D

- anonymous

yw

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