Bookworm14
  • Bookworm14
Homework help with Factoring? Please? Thank you!! I need to see how to work it out, that way I can actually learn this, draw it out if you can? I will post it below thanks !
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Bookworm14
  • Bookworm14
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anonymous
  • anonymous
you got my attention!
anonymous
  • anonymous
ok you have choices so it make it easier

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Bookworm14
  • Bookworm14
Hey Satellite! long time no see! I have already used the slide and divide method, but i think im gonna have to use grouping, which i am not very good at
anonymous
  • anonymous
when you multiply out any of those "binomials" the last term, the number, will be what you get when you multiply the two constants together that has to give you \(-30\)
anonymous
  • anonymous
@AliLnn sure
anonymous
  • anonymous
to it could be A \((2b+5)(2b-6)\) or it could be C \((2b-5)(2b+6)\) because \(-5\times 6=-30\) it can't be the other two
anonymous
  • anonymous
damn typo sorry
Bookworm14
  • Bookworm14
I have to show my work for this, that is why i needed step by step (possibly drawn out) examples -_- sorry and your fine darlin, take your time haha
anonymous
  • anonymous
\[(2b+5)(5b-6)\] or \[(2b-5)(5b+6)\]
anonymous
  • anonymous
i have no idea what "work" you have to show to do this you pretty much have to grind it til you find it
anonymous
  • anonymous
you can check which ones of the above give you a "middle term" of \(-13b\)
anonymous
  • anonymous
which will of course be C
Bookworm14
  • Bookworm14
you know what, im just gonna show my work for working out the answer choices and that should be good enough! lol and thank you, my mind was grinding gears over nothin over here haha
anonymous
  • anonymous
you can guess it will be \((2b+?)(5b+?)\) and then reason that one of those has to be positive, the other negative, since the product is negative
anonymous
  • anonymous
you get a bunch of choices, but since you really only have 4 possible answers, you can check the one that is right otherwise it is very tedious to go through all the possible combinations
Bookworm14
  • Bookworm14
Thanks Love! :D
anonymous
  • anonymous
yw

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