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anonymous

  • one year ago

What is the formula for factoring a^2+b^2?

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  1. anonymous
    • one year ago
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    Specifically, my question is 8r^6+27s^12.

  2. anonymous
    • one year ago
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    It concerns factoring.

  3. anonymous
    • one year ago
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    \[a^2+b^2=a^2-(-b^2)=\left( a^2-\iota^2b^2 \right)=\left( a+\iota b \right)\left( a-\iota b \right)\]

  4. anonymous
    • one year ago
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    Is there a more simple version of this formula @surjithayer ?

  5. anonymous
    • one year ago
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    \[8r^6+27s^{12}=\left( 2r^2 \right)^3+\left( 3s^4 \right)^3=?\]

  6. anonymous
    • one year ago
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    Is that really the formula I need to use to solve the problem @surjithayer ?

  7. anonymous
    • one year ago
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    yes \[a^3+b^3=\left( a+b \right)\left( a^2-ab+b^2 \right)\]

  8. anonymous
    • one year ago
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    Ah, okay. Thank you. I am now going to work on it. :-)

  9. anonymous
    • one year ago
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    That was a hard question. (2r^2+3s^4)(4r^4-6r^4s^6+9s^3)

  10. anonymous
    • one year ago
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    yw

  11. anonymous
    • one year ago
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    R u asking what that is and its A²+b ²=c² and its called the pythagorean theorem

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