anonymous
  • anonymous
the length of a rectangle is 9 feet more than the width . if the perimeter is 174 feet, what are the length and the width
Mathematics
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SOLVED
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chestercat
  • chestercat
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steve816
  • steve816
x + x + x + 9 + x + 9 = 174
steve816
  • steve816
x is the length of the width, and since the length is 9 more than the width, it would be x + 9
RagingSquirrel
  • RagingSquirrel
So you have a rectangle that looks like this. |dw:1443238547361:dw| Since the perimeter is just 2w+2l, you can write an equation. P=2w+2l Now plug in your details. We know that P is 174 feet. 174=2w+2l We know that the length is (w+9) and the width is just w. Plug those in. 174=2w+2(w+9) Now solve this.

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steve816
  • steve816
All you have to do is solve now :)
steve816
  • steve816
Great response @RagingSquirrel
RagingSquirrel
  • RagingSquirrel
Thanks! :) I always appreciate recognition
anonymous
  • anonymous
174=4w+18
RagingSquirrel
  • RagingSquirrel
Good! Now solve for w. Can you do that?
anonymous
  • anonymous
174=4w+18?
RagingSquirrel
  • RagingSquirrel
You need to get the w all by itself. 174=4w+18 Subtract 18 from both sides. 174-18=4w+18-18 156=4w There's still a 4 in the way. To get that out, you need to divide both sides by 4. 156 divided by 4=4w divided by 4 39=w Flip it so w comes first. Then add your label. w=39 feet
RagingSquirrel
  • RagingSquirrel
Your width is 39 feet. To find the length, just plug 39 in for w in our equation for length. l=w+9 l=(39)+9 length=48 feet

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