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- anonymous

the length of a rectangle is 9 feet more than the width . if the perimeter is 174 feet, what are the length and the width

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- anonymous

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- steve816

x + x + x + 9 + x + 9 = 174

- steve816

x is the length of the width, and since the length is 9 more than the width, it would be x + 9

- RagingSquirrel

So you have a rectangle that looks like this.
|dw:1443238547361:dw|
Since the perimeter is just 2w+2l, you can write an equation.
P=2w+2l
Now plug in your details. We know that P is 174 feet.
174=2w+2l
We know that the length is (w+9) and the width is just w. Plug those in.
174=2w+2(w+9)
Now solve this.

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- steve816

All you have to do is solve now :)

- steve816

Great response @RagingSquirrel

- RagingSquirrel

Thanks! :) I always appreciate recognition

- anonymous

174=4w+18

- RagingSquirrel

Good! Now solve for w. Can you do that?

- anonymous

174=4w+18?

- RagingSquirrel

You need to get the w all by itself.
174=4w+18
Subtract 18 from both sides.
174-18=4w+18-18
156=4w
There's still a 4 in the way. To get that out, you need to divide both sides by 4.
156 divided by 4=4w divided by 4
39=w
Flip it so w comes first. Then add your label.
w=39 feet

- RagingSquirrel

Your width is 39 feet. To find the length, just plug 39 in for w in our equation for length.
l=w+9
l=(39)+9
length=48 feet

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