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anonymous

  • one year ago

the length of a rectangle is 9 feet more than the width . if the perimeter is 174 feet, what are the length and the width

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  1. steve816
    • one year ago
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    x + x + x + 9 + x + 9 = 174

  2. steve816
    • one year ago
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    x is the length of the width, and since the length is 9 more than the width, it would be x + 9

  3. RagingSquirrel
    • one year ago
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    So you have a rectangle that looks like this. |dw:1443238547361:dw| Since the perimeter is just 2w+2l, you can write an equation. P=2w+2l Now plug in your details. We know that P is 174 feet. 174=2w+2l We know that the length is (w+9) and the width is just w. Plug those in. 174=2w+2(w+9) Now solve this.

  4. steve816
    • one year ago
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    All you have to do is solve now :)

  5. steve816
    • one year ago
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    Great response @RagingSquirrel

  6. RagingSquirrel
    • one year ago
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    Thanks! :) I always appreciate recognition

  7. anonymous
    • one year ago
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    174=4w+18

  8. RagingSquirrel
    • one year ago
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    Good! Now solve for w. Can you do that?

  9. anonymous
    • one year ago
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    174=4w+18?

  10. RagingSquirrel
    • one year ago
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    You need to get the w all by itself. 174=4w+18 Subtract 18 from both sides. 174-18=4w+18-18 156=4w There's still a 4 in the way. To get that out, you need to divide both sides by 4. 156 divided by 4=4w divided by 4 39=w Flip it so w comes first. Then add your label. w=39 feet

  11. RagingSquirrel
    • one year ago
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    Your width is 39 feet. To find the length, just plug 39 in for w in our equation for length. l=w+9 l=(39)+9 length=48 feet

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