What is the value of the following expression when x=3 and y=-2? 4x-y2

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What is the value of the following expression when x=3 and y=-2? 4x-y2

Mathematics
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can you put those values into the expression
just the order of ops thing like last time i think

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The expression is this right? \[\Large 4x - y^2\]
yes!
to start off, replace every x with 3 (since x = 3) \[\Large 4\color{red}{x} - y^2\] \[\Large 4(\color{red}{3}) - y^2\]
Sorry brain fart. and I really don't know how to use this site.
Then replace every y with -2 \[\Large 4(3) - \color{red}{y}^2\] \[\Large 4(3) - (\color{red}{-2})^2\]
at this point, you either use pen/paper to compute or a calculator to compute
Well 4*3 equals 64.
4*3 does not equal 64
you might be thinking of \(\Large 4^3\)
That's what I meant. How you drew it out before kind of like \[4*4*4\]
Something like that lol
well in the case of 4*3, it's simply 4 times 3, which is 12
that's different from 4^3, which is 4 to the third power
Oh ok!
btw, 4(3) is another way of saying 4*3
Oh ok!:)
Talking about the final answer. From my calulations, its positive?
The answer is positive. Yes
I stuck between 8 and 16.
what is (-2)^2 equal to?
-4? I have a feeling that that's incorrect.
we multiply -2 by itself twice
(-2)^2 = (-2)*(-2) = ??
-8?
you were correct about the 4 part, it's just positive and not negative -2 times -2 = +4
negative times negative = positive
Oh!!!!!
\[\Large \color{red}{4(3)} - \color{blue}{(-2)^2}\] \[\Large \color{red}{12} - \color{blue}{4}\]
8
yep
Thats the final answer?
yes it is

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