anonymous
  • anonymous
Medal and fan reward I KNOW HOW TO WORK THIS OUT, I JUST WANT THE ANSWER (i'm just double checking to see if I'm right or not) a) If a sample containing 2.00 mL of nitroglycerin (density= 1.592 g/ml) is detonated, how mahy total moles of gas are produced? b) If each mole of gas occupies 55 L under the conditions of the explosion, how many liters of gas are produced? c) How many grams of N2 are produced in the detonation?
Chemistry
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anonymous
  • anonymous
Medal and fan reward I KNOW HOW TO WORK THIS OUT, I JUST WANT THE ANSWER (i'm just double checking to see if I'm right or not) a) If a sample containing 2.00 mL of nitroglycerin (density= 1.592 g/ml) is detonated, how mahy total moles of gas are produced? b) If each mole of gas occupies 55 L under the conditions of the explosion, how many liters of gas are produced? c) How many grams of N2 are produced in the detonation?
Chemistry
katieb
  • katieb
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anonymous
  • anonymous
What are you answers?
anonymous
  • anonymous
your*
anonymous
  • anonymous
a) .102 b) 5.59 c) .437 (a friend of sort of helped me with it)

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anonymous
  • anonymous
@Shalante what u get?
anonymous
  • anonymous
Yes that is correct!
anonymous
  • anonymous
wait PLEASE @Shalante can you PLEASE explain to me how you got letter c
anonymous
  • anonymous
Yes Grams of nitroglycerin is 3.184grams Molar mass of nitroglycerin is 227g/mol There are 6 moles of N2 for every 4 mols of nitroglycerin (C3H5N3O9) N2 molar mass is 28g/mol
anonymous
  • anonymous
\[\frac{ 3.184g C _{3}H _{5}N _{3}O _{9} }{ 1} \times \frac{ 1mol C3H5N3O9 }{ 227g C3H5N3O9 } \times \frac{ 6mol N2 }{ 4mol C3H5N3O9 } \times \frac{ 28.00g N2 }{ 1mol N2 }\]
anonymous
  • anonymous
when I did that I got .58
anonymous
  • anonymous
Detonation of nitroglycerin reaction \[4C _{3}H _{5}N _{3}O _{9}\rightarrow 12CO _{2}+ 6N _{2}+O _{2}+10H _{2}O\]
anonymous
  • anonymous
Lemme see.
anonymous
  • anonymous
but when I multiplied I got .589 @ Shalante what am I doing wrong
anonymous
  • anonymous
anonymous
  • anonymous
Gimme a second.
anonymous
  • anonymous
K THANKS! YOU'RE THE BEST
anonymous
  • anonymous
Actually it is 0.58. I am right.
anonymous
  • anonymous
Your friend was wrong.
anonymous
  • anonymous
oh ok then
anonymous
  • anonymous
I trust you
anonymous
  • anonymous
Haha, I am glad you told me to show you the steps.
anonymous
  • anonymous
The dimensional analysis looked close between 0.30-0.7 so I assumed you got it right. Thats is actually better for me to do it than check it lol.
anonymous
  • anonymous
lol and for b it's just 55L times the answer I got for a right?
anonymous
  • anonymous
Yeah because they to want to know the number of moles with a different amount of liter.
anonymous
  • anonymous
all right thx
anonymous
  • anonymous
No problem! I need to sleep now. Good luck with the rest

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