Discriminant help?

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Discriminant help?

Mathematics
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Find the value of the discriminant for the quadratic equation below. Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula. Then use the value to determine how many real number solutions each equation has. x^2 + 6x - 3 = 0

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Other answers:

Do you know the formula for the discriminant?
In the general expression for a quadratic \[\large ax^{2}+bx+c=0\] the discriminant is \[\large b^{2}-4ac\] In the given quadratic, a = 1; b = 6 and c = -3 Now you just need to plug in these values.
6^2 - 4(1)(-3) ?
Correct.
my final answer would be 48?
Correct again.
at the end of the question it says " Then use the value to determine how many real number solutions each equation has."
The value of the discriminant is positive, but is not a perfect square. Therefore there are two real roots which are irrational and unequal.
Thats all i need to do right?
That is right.
Thank u.
You're welcome :)

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