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anonymous
 one year ago
the values of x for which the graphs of y=x+2,y^2=4x intersect are:
a. 2 and 2
b. 2
c. 2
d. 0
e. none of these
anonymous
 one year ago
the values of x for which the graphs of y=x+2,y^2=4x intersect are: a. 2 and 2 b. 2 c. 2 d. 0 e. none of these

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zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0\[\large\rm y=x+2,\qquad\qquad y^2=4x\]We have a couple ways to approach this... Hmm, let's try solving each equation for x.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0In the first equation, subtract 2 gives us,\[\large\rm y2=\color{orangered}{x}\]And in the second equation, dividing by 4 gives us,\[\large\rm \frac{y^2}{4}=\color{orangered}{x}\]They will intersect when these x's are the same, which means the equations are the same.\[\large\rm y2=\frac{y^2}{4}\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Multiply by 4,\[\large\rm 4y8=y^2\]Move everything to one side,\[\large\rm y^24y+8=0\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0It looks like this `is not` going to factor nicely. Try using your quadratic formula:\[\large\rm y=\frac{b\pm\sqrt{b^24ac}}{2a}\]Plug in the values, what does it tell you? :)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Hmm +_+ Well, we're trying to find our ycoordinate, and we can then use that to find the xcoordinate of intersection. What did you get for the yvalue? Use the formula.

jiteshmeghwal9
 one year ago
Best ResponseYou've already chosen the best response.1\(y=x+2\) \(y^2=4x\) From above eqn \(y^2=4(y2)\) \(y^24y+8=0\) solve eqn either by quadratic formula or factorization.

jiteshmeghwal9
 one year ago
Best ResponseYou've already chosen the best response.1\[y=\frac{4 \pm \sqrt{1632}}{2}\]and \[ x=y2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so im right @jiteshmeghwal9

jiteshmeghwal9
 one year ago
Best ResponseYou've already chosen the best response.1\[y=\frac{4 \pm 4 \iota}{2}=2\pm2 \iota\] \[x=y2=2\pm2 \iota 2\]\[x= \pm 2 \iota\]
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