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anonymous
 one year ago
A ball is thrown vertically upwards from the ground. It rises to a height of 10 m and then falls and bounces. After each bounce it rises vertically to 2/3 of the height from which it fell
Find the height to which the ball bounces after the nth impact with the ground.
I will put the answer I got now.
anonymous
 one year ago
A ball is thrown vertically upwards from the ground. It rises to a height of 10 m and then falls and bounces. After each bounce it rises vertically to 2/3 of the height from which it fell Find the height to which the ball bounces after the nth impact with the ground. I will put the answer I got now.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[10 \times (\frac{ 2 }{ 3 })^{k1}\] Thats what I got

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The answer is \[10 \times (\frac{ 2 }{ 3 })^{n}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Could somebody please explain how they got that?

baru
 one year ago
Best ResponseYou've already chosen the best response.0if the answer was (k1), then after the first bounce the ball would rise by 10* (2/3)^0 which is equal to 10. thats why its "n"

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0\[n\text{ is the number of times it bounces off the ground, so that becomes}\]\[\left(\frac{2}{3}\right)^{n}\]\[\text{multiply that by the original height bounced of 10 meters and}\]\[10\times\left(\frac{2}{3}\right)^{n}\]Basically it is saying "imagine 10 m per bounce scenario and then multiply 10 m by the amount of bounces, then 2/3 that"

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0@Zas does this help?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think so, thank you!

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0You're welcome. :]
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