A ball is thrown vertically upwards from the ground. It rises to a height of 10 m and then falls and bounces. After each bounce it rises vertically to 2/3 of the height from which it fell
Find the height to which the ball bounces after the nth impact with the ground.
I will put the answer I got now.

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\[10 \times (\frac{ 2 }{ 3 })^{k-1}\]
Thats what I got

The answer is \[10 \times (\frac{ 2 }{ 3 })^{n}\]

Could somebody please explain how they got that?

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