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Diana.xL

  • one year ago

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  1. Diana.xL
    • one year ago
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    Find the value of the discriminant for the quadratic equation below. Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula. Then use the value to determine how many real number solutions each equation has. 3x^2 + 2x +1 = 0

  2. Diana.xL
    • one year ago
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    @imqwerty

  3. Diana.xL
    • one year ago
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    @ganeshie8

  4. imqwerty
    • one year ago
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    if u have any quadratic equation like this-\[ax^2+bx+c=0\]then the discriminant[D] is given by -\[D=b^2-4ac\] so we have the equation-\[3x^2+2x+1 \]comparing it with the standard equation ax^2+bx+c=0 we can see that a=2, b=2, c=1 so substituting these values in the discriminant formula we get\[D=2^2-4(3)(1)\]\[D=4-12 => D=-8\] the solutions x can be represented by-\[x=\frac{ -b \pm \sqrt{D} }{ 2a }\]but since D is negative root(D) doesn't exists so the roots are unreal

  5. Diana.xL
    • one year ago
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    Thank you!

  6. imqwerty
    • one year ago
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    np :)

  7. Diana.xL
    • one year ago
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    btw up there did you mean a = 3?

  8. baru
    • one year ago
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    yep...a is 3. but it dosent change the outcome, still no real solutions

  9. imqwerty
    • one year ago
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    yes a=3

  10. Diana.xL
    • one year ago
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    alright. thnx :)

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