Diana.xL
  • Diana.xL
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Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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Diana.xL
  • Diana.xL
Find the value of the discriminant for the quadratic equation below. Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula. Then use the value to determine how many real number solutions each equation has. 3x^2 + 2x +1 = 0
Diana.xL
  • Diana.xL
@imqwerty
Diana.xL
  • Diana.xL
@ganeshie8

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imqwerty
  • imqwerty
if u have any quadratic equation like this-\[ax^2+bx+c=0\]then the discriminant[D] is given by -\[D=b^2-4ac\] so we have the equation-\[3x^2+2x+1 \]comparing it with the standard equation ax^2+bx+c=0 we can see that a=2, b=2, c=1 so substituting these values in the discriminant formula we get\[D=2^2-4(3)(1)\]\[D=4-12 => D=-8\] the solutions x can be represented by-\[x=\frac{ -b \pm \sqrt{D} }{ 2a }\]but since D is negative root(D) doesn't exists so the roots are unreal
Diana.xL
  • Diana.xL
Thank you!
imqwerty
  • imqwerty
np :)
Diana.xL
  • Diana.xL
btw up there did you mean a = 3?
baru
  • baru
yep...a is 3. but it dosent change the outcome, still no real solutions
imqwerty
  • imqwerty
yes a=3
Diana.xL
  • Diana.xL
alright. thnx :)

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