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Diana.xL
 one year ago
help
Diana.xL
 one year ago
help

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Diana.xL
 one year ago
Best ResponseYou've already chosen the best response.0Find the value of the discriminant for the quadratic equation below. Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula. Then use the value to determine how many real number solutions each equation has. 3x^2 + 2x +1 = 0

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.2if u have any quadratic equation like this\[ax^2+bx+c=0\]then the discriminant[D] is given by \[D=b^24ac\] so we have the equation\[3x^2+2x+1 \]comparing it with the standard equation ax^2+bx+c=0 we can see that a=2, b=2, c=1 so substituting these values in the discriminant formula we get\[D=2^24(3)(1)\]\[D=412 => D=8\] the solutions x can be represented by\[x=\frac{ b \pm \sqrt{D} }{ 2a }\]but since D is negative root(D) doesn't exists so the roots are unreal

Diana.xL
 one year ago
Best ResponseYou've already chosen the best response.0btw up there did you mean a = 3?

baru
 one year ago
Best ResponseYou've already chosen the best response.0yep...a is 3. but it dosent change the outcome, still no real solutions
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