## Diana.xL one year ago help

1. Diana.xL

Find the value of the discriminant for the quadratic equation below. Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula. Then use the value to determine how many real number solutions each equation has. 3x^2 + 2x +1 = 0

2. Diana.xL

@imqwerty

3. Diana.xL

@ganeshie8

4. imqwerty

if u have any quadratic equation like this-$ax^2+bx+c=0$then the discriminant[D] is given by -$D=b^2-4ac$ so we have the equation-$3x^2+2x+1$comparing it with the standard equation ax^2+bx+c=0 we can see that a=2, b=2, c=1 so substituting these values in the discriminant formula we get$D=2^2-4(3)(1)$$D=4-12 => D=-8$ the solutions x can be represented by-$x=\frac{ -b \pm \sqrt{D} }{ 2a }$but since D is negative root(D) doesn't exists so the roots are unreal

5. Diana.xL

Thank you!

6. imqwerty

np :)

7. Diana.xL

btw up there did you mean a = 3?

8. baru

yep...a is 3. but it dosent change the outcome, still no real solutions

9. imqwerty

yes a=3

10. Diana.xL

alright. thnx :)