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Diana.xL

  • one year ago

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  1. Diana.xL
    • one year ago
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    x^2+4x +4 = 0

  2. Diana.xL
    • one year ago
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    @imqwerty

  3. kittiwitti1
    • one year ago
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    What do you want to do with this equation?

  4. imqwerty
    • one year ago
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    1)compare this equation with\[ax^2+bx+x=0\] 2)identify a,b,c 3)apply this formula to find discriminant\[D=b^2-4ac\]

  5. kittiwitti1
    • one year ago
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    \[x^{2}+4x+4=0\text{ Solve for x?}\]

  6. Diana.xL
    • one year ago
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    x^2 + 4x +4 = 0 a = 1, b = 4, c = 4 D = 4x - 4(1)(4)

  7. Diana.xL
    • one year ago
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    would my final answer be 0?

  8. imqwerty
    • one year ago
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    wait u wanna knw discriminant or roots?

  9. Diana.xL
    • one year ago
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    yes i do. its just like the other question u answered.

  10. kittiwitti1
    • one year ago
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    If you're solving for x then the quadratic formula would be of better use:\[x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}\]

  11. kittiwitti1
    • one year ago
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    What do you mean by your final answer then?

  12. imqwerty
    • one year ago
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    ok yes D=0 is correct

  13. Diana.xL
    • one year ago
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    Find the value of the discriminant for each quadratic equation below. Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula. Then use the value to determine how many real number solutions each equation has.

  14. Diana.xL
    • one year ago
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    this is what its asking

  15. kittiwitti1
    • one year ago
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    Okay. Please post that next time because I got confused :p

  16. Diana.xL
    • one year ago
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    haha ok

  17. Diana.xL
    • one year ago
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    @imqwerty The quadratic equation will be having only one real root.?

  18. kittiwitti1
    • one year ago
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    I suck at discriminants though so yeah ask the great qwerty ^^

  19. imqwerty
    • one year ago
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    back

  20. imqwerty
    • one year ago
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    yes because D=0 there is only 1 real root

  21. Diana.xL
    • one year ago
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    ok thnx!!

  22. imqwerty
    • one year ago
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    np :)

  23. Diana.xL
    • one year ago
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    can u help with one more?

  24. imqwerty
    • one year ago
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    yea y not

  25. Diana.xL
    • one year ago
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    Find the value of the discriminant for each quadratic equation below. Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula. Then use the value to determine how many real number solutions each equation has. 5x^2 + x = 4

  26. imqwerty
    • one year ago
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    ok do the same steps

  27. Diana.xL
    • one year ago
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    a = 5, b = 1, c = 4 D = 1 - 4(5)(4) D = 81. is it correct?

  28. imqwerty
    • one year ago
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    back

  29. imqwerty
    • one year ago
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    1st u need to convert the equation into this form-\[ax^2+bx+c=0\]so there shuld be a 0 on the left hand side can u bring a zero out there by subtracting 4 from both sides :)

  30. Diana.xL
    • one year ago
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    i dont understand

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