## kittiwitti1 one year ago Trig questions. The answer deadline is up so I cannot submit the answers anymore, but feel free to answer and help out if you can. A) The figure below is a simplified model of a Ferris wheel with diameter 230 feet. The top of the wheel is 240 feet above the ground. If θ is the central angle formed as a rider moves from position P0 to position P1, find the rider's height above the ground h when θ is 120°. Diagram: http://prntscr.com/8kn5ag B) Suppose each edge of the cube shown in the figure is 9.00 inches long. Find the measure of the angle formed by diagonals CF and CH. Round your answer to the nearest tenth of a degree. Diagram: http://prntscr.com/8lbcvd **Variable version: Suppose each edge of the cube shown in the figure is x inches long. Find the measure of the angle formed by diagonals DE and DG. Round your answer to the nearest tenth of a degree. Diagram http://prntscr.com/8lbe3e

1. Hero

Okay give me some minutes to figure out the solution

2. kittiwitti1

Alright

3. kittiwitti1

There is an issue with showing how many users are actually viewing this question. Lol

4. Hero

Almost finished

5. kittiwitti1

Gotcha

6. kittiwitti1

Take your time, I've got other problems to work on in the meantime :)

7. kittiwitti1

@Hero I may be able to solve question A. Are you okay with helping me solve the other two questions?

8. kittiwitti1

scratch that I got stuck

9. Hero

I thought I'd be able to solve this but I haven't worked with it in a While and It's very late here. I don't know why you wait until now to want to do this We and have done it at any point during the day.

10. kittiwitti1

I just woke up an hour ago. Lol

11. Hero

I'm going to post the solution but it will take a bit longer Just be patient please.

12. kittiwitti1

Okay

13. baru

i think B can be answered using vectors...

14. kittiwitti1

The deadline for the question submission is up.

15. baru

if u set it up so that the cube lies in the first octant with C at the origin, then CH = <9,9,0> and CF is <9,9,9>

16. baru

oh

17. kittiwitti1

18. kittiwitti1

...except this class has not taught vectors yet. I do know vectors, but the class hasn't taught us vectors yet. At least I don't think they have... But you can proceed. I know vectors so I'll just use vectors :p

19. baru

oh ok... then never mind. But the next step would be to use "dot product" in case you are curious. its a formula that allows us to find the angle between any two vectors. you will definitely come across it :)

20. kittiwitti1

21. kittiwitti1

I forgot how to dot-product actually... it's been two years ^^;

22. baru

if you have two vectors A=<a1,a2,a3> and B=<b1,b2,b3> then the dot product of A and B is (a1b1+a2b2 + a3b3) OR (magnitude of A)(magnitude of B)( cosine of angle between them) so, $81+81+0= \sqrt{9^2 +9^2 +0} \times \sqrt{9^2 +9^2 +9^2}\times \cos(\theta)$

23. baru

solve for theta 35.2 degrees

24. baru

does it match with the answer you got?

25. kittiwitti1

Um... I was working on my psych homework lol I might have to go, so if you wanna do this tomorrow?

26. baru

no prob

27. kittiwitti1

Thanks :D

28. Hero

I have the solution. I will post in five minutes Or less.

29. kittiwitti1

Hero, take your time. My answer submission form is already expired so I am fine with waiting however line for the solution. :]

30. Hero

Well, the solution is for part A that's all I have time for sorry.

31. kittiwitti1

however long* Okay that's fine you can do it later :]

32. FireKat97

You can do B without vectors quite simply as well, |dw:1444204348370:dw|

33. FireKat97

|dw:1444204444350:dw| so we can find CH using python, and its simply $\sqrt{9^2 + 9^2}$ which simplifies to $\sqrt{162}$

34. FireKat97

|dw:1444204536394:dw| again using pythag $\tanø = \frac{ 9 }{ √162 }$ therefore ø = 35.2 @kittiwitti1

35. FireKat97

Also, did you understand part A @kittiwitti1?

36. kittiwitti1

Sorry, what's up? Just logged on-