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kittiwitti1

  • one year ago

Trig questions. The answer deadline is up so I cannot submit the answers anymore, but feel free to answer and help out if you can. A) The figure below is a simplified model of a Ferris wheel with diameter 230 feet. The top of the wheel is 240 feet above the ground. If θ is the central angle formed as a rider moves from position P0 to position P1, find the rider's height above the ground h when θ is 120°. Diagram: http://prntscr.com/8kn5ag B) Suppose each edge of the cube shown in the figure is 9.00 inches long. Find the measure of the angle formed by diagonals CF and CH. Round your answer to the nearest tenth of a degree. Diagram: http://prntscr.com/8lbcvd **Variable version: Suppose each edge of the cube shown in the figure is x inches long. Find the measure of the angle formed by diagonals DE and DG. Round your answer to the nearest tenth of a degree. Diagram http://prntscr.com/8lbe3e

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  1. Hero
    • one year ago
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    Okay give me some minutes to figure out the solution

  2. kittiwitti1
    • one year ago
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    Alright

  3. kittiwitti1
    • one year ago
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    There is an issue with showing how many users are actually viewing this question. Lol

  4. Hero
    • one year ago
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    Almost finished

  5. kittiwitti1
    • one year ago
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    Gotcha

  6. kittiwitti1
    • one year ago
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    Take your time, I've got other problems to work on in the meantime :)

  7. kittiwitti1
    • one year ago
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    @Hero I may be able to solve question A. Are you okay with helping me solve the other two questions?

  8. kittiwitti1
    • one year ago
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    scratch that I got stuck

  9. Hero
    • one year ago
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    I thought I'd be able to solve this but I haven't worked with it in a While and It's very late here. I don't know why you wait until now to want to do this We and have done it at any point during the day.

  10. kittiwitti1
    • one year ago
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    I just woke up an hour ago. Lol

  11. Hero
    • one year ago
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    I'm going to post the solution but it will take a bit longer Just be patient please.

  12. kittiwitti1
    • one year ago
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    Okay

  13. baru
    • one year ago
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    i think B can be answered using vectors...

  14. kittiwitti1
    • one year ago
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    The deadline for the question submission is up.

  15. baru
    • one year ago
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    if u set it up so that the cube lies in the first octant with C at the origin, then CH = <9,9,0> and CF is <9,9,9>

  16. baru
    • one year ago
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    oh

  17. kittiwitti1
    • one year ago
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    No, go ahead. I would still like to know the answer.

  18. kittiwitti1
    • one year ago
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    ...except this class has not taught vectors yet. I do know vectors, but the class hasn't taught us vectors yet. At least I don't think they have... But you can proceed. I know vectors so I'll just use vectors :p

  19. baru
    • one year ago
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    oh ok... then never mind. But the next step would be to use "dot product" in case you are curious. its a formula that allows us to find the angle between any two vectors. you will definitely come across it :)

  20. kittiwitti1
    • one year ago
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    No it's okay go ahead

  21. kittiwitti1
    • one year ago
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    I forgot how to dot-product actually... it's been two years ^^;

  22. baru
    • one year ago
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    if you have two vectors A=<a1,a2,a3> and B=<b1,b2,b3> then the dot product of A and B is (a1b1+a2b2 + a3b3) OR (magnitude of A)(magnitude of B)( cosine of angle between them) so, \[81+81+0= \sqrt{9^2 +9^2 +0} \times \sqrt{9^2 +9^2 +9^2}\times \cos(\theta)\]

  23. baru
    • one year ago
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    solve for theta 35.2 degrees

  24. baru
    • one year ago
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    does it match with the answer you got?

  25. kittiwitti1
    • one year ago
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    Um... I was working on my psych homework lol I might have to go, so if you wanna do this tomorrow?

  26. baru
    • one year ago
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    no prob

  27. kittiwitti1
    • one year ago
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    Thanks :D

  28. Hero
    • one year ago
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    I have the solution. I will post in five minutes Or less.

  29. kittiwitti1
    • one year ago
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    Hero, take your time. My answer submission form is already expired so I am fine with waiting however line for the solution. :]

  30. Hero
    • one year ago
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    Well, the solution is for part A that's all I have time for sorry.

  31. kittiwitti1
    • one year ago
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    however long* Okay that's fine you can do it later :]

  32. FireKat97
    • one year ago
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    You can do B without vectors quite simply as well, |dw:1444204348370:dw|

  33. FireKat97
    • one year ago
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    |dw:1444204444350:dw| so we can find CH using python, and its simply \[\sqrt{9^2 + 9^2}\] which simplifies to \[\sqrt{162}\]

  34. FireKat97
    • one year ago
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    |dw:1444204536394:dw| again using pythag \[\tanø = \frac{ 9 }{ √162 }\] therefore ø = 35.2 @kittiwitti1

  35. FireKat97
    • one year ago
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    Also, did you understand part A @kittiwitti1?

  36. kittiwitti1
    • one year ago
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    Sorry, what's up? Just logged on-

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