Diana.xL
  • Diana.xL
help?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Diana.xL
  • Diana.xL
Find the value of the discriminant for each quadratic equation below. Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula. Then use the value to determine how many real number solutions each equation has. 5x^2 + x = 4
misty1212
  • misty1212
HI!!
Diana.xL
  • Diana.xL
Hey :)

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misty1212
  • misty1212
start by setting it equal to zero go from \[5x^2 + x = 4\] to \[5x^2+x-4=0\]
misty1212
  • misty1212
\[\large \color{red}ax^2+\color{blue}bx+\color{green}c=0\] \[\huge \color{red}5x^2+\color{blue}1x+\color{green}{-4}=0\]
misty1212
  • misty1212
then as @risn said compute \[\huge \color{blue}b^2-4\times \color{red}a\times \color{green}c\]
Diana.xL
  • Diana.xL
D= 1 - 4 (1)(-4)?
misty1212
  • misty1212
nope
misty1212
  • misty1212
\(\color{red}a=\color{red}{5}\)
Diana.xL
  • Diana.xL
oh sorry. D = 1-4(5)(-4)
misty1212
  • misty1212
yeah that is right what do you get?
Diana.xL
  • Diana.xL
81?
Diana.xL
  • Diana.xL
as my final answer?
misty1212
  • misty1212
yeah me too
Diana.xL
  • Diana.xL
at the end of the question it asks us "Then use the value to determine how many real number solutions each equation has".
misty1212
  • misty1212
that is the answer to Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula.
misty1212
  • misty1212
ok two steps here 81 is positive, so there are two real solutions also 81 is a "perfect square" it is the square of 9 that means both solutions are rational numbers
Diana.xL
  • Diana.xL
oh ok! thank u so much! :)
misty1212
  • misty1212
in fact that means \[5x^2+x-4=0\] can be solved by factoring you get \[(5x-4)(x+1)=0\] so \[x=\frac{4}{5}\] or \[x=-1\]
misty1212
  • misty1212
\[\color\magenta\heartsuit\]

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