anonymous
  • anonymous
What is the common ratio between successive terms in the sequence? 27, 9, 3, 1,1/3 , 1/9, 1/27, ... A. –3 B. –1/3 C. 1/3 D. 3
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

phi
  • phi
the are asking what do you multiply 27 by to get 9? 27 * x = 9 where x is the unknown number if you divide both sides by 27 you get x= 9/27 you can simplify that fraction to get the answer.
phi
  • phi
or what do you multiply 9 by to get 3? or what do you multiply 3 by to get 1 ?
anonymous
  • anonymous
3 right? @phi

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

phi
  • phi
are you saying 27*3 = 9 ?
DanJS
  • DanJS
common ratio of a geometric series r, the ratio of (n+1)/n term
DanJS
  • DanJS
every term divided by the previous term should give you the same number as the common ratio
DanJS
  • DanJS
9 / 27 3 / 9 1/3 .....
DanJS
  • DanJS
all successive have common ratio r = 1/3
anonymous
  • anonymous
thank you @DanJS
Jaynator495
  • Jaynator495
Welcome To OpenStudy! Here you will find great helpers and friends, a community of students that help students! We hope you enjoy the experience!

Looking for something else?

Not the answer you are looking for? Search for more explanations.