Diana.xL one year ago help

1. Diana.xL

Find the value of the discriminant for each quadratic equation below. Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula. Then use the value to determine how many real number solutions each equation has. 2x^2 -3x = -5

2. Diana.xL

@ganeshie8

the discriminant is -31 hold on i gotta do simplest form...

4. anonymous

The discriminant is -31, using the formula ax^2 + bx + c = 0 (2x^2 + -3x + 5 = 0) The simplest form of this equation, step by step - Combine like terms: 2x^2 - 3x + 5 = 0 Apply the Quadratic Formula: $-b + \sqrt{b^2-4ac} \over 2a$ $-b-\sqrt{b^2-4ac} \over 2a$ So, in this equation, a = 2, b = -3, c = 5. $x = 3 + \sqrt{31} \over 4$ and $3 - \sqrt{31} \over 4$