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anonymous
 one year ago
Need help with Applied Linear Algebra
anonymous
 one year ago
Need help with Applied Linear Algebra

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I found the reduced echelon form to be : dw:1443287325608:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and now I do not know what to do, So I know that there will never be a "No Solution" to this system. and I know there will be a unique solution when a=0 (Correct me if I am wrong) but when will there be infinite solution?

surry99
 one year ago
Best ResponseYou've already chosen the best response.0Assuming your reduced matrix is correct, the only solution would be a=0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it will just be a trivial solution

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but what if I just have as a row echelon form like this: dw:1443288786467:dw the answer would change then, then "a" will have to equal 1 for their to be a trivial solution

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0should i use row echelon form or reduced form?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\left\begin{matrix}1 & 1 &4 \\ 3 & 2 &10\\a&3&8\end{matrix}\right=1[\left( 2 \right)\left( 8 \right)10*3](1)[3*(8)10a]+4[3*3+2a]\] =16302410a+36+8a =22a it has infinite solutions if22a=0 or a=1 no solution if \[a \neq1\] only trivial solution x1=x2=x3=0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but homogenous systems never have "no solutions". so when it asks when It has no solution I would have to write "never". wait that doesnt make sense, if a=1 I dont think there will be a inifinite solutions because then (22a)x3=0 so x3 must equal 0. making all the other variables(x1, x2, x3=0) so there will be only 1 solution not infinite right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so ultimately when it asks when does the system have unique solution I would have to write when a=1. and when it asks when does it have infinite solution, I would have to write "never". is that correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you are correct if ax=0 then either a=0 or x=0
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