how to factorise and solve -x^2 - 8

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how to factorise and solve -x^2 - 8

Mathematics
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8 isn't a perfect square, so that can't be factored without using radicals. As for solving it, is that equal to something?
that's what I thought but I've got to draw it as a graph
there's y= (x-2)(x+2)(x+2) and y= -x^2 -8

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I've only got to sketch it but I need the x intercept I think
so you need to sketch both of those and find the solution/intersection point?
Yep
ok. for the first one you can use the x-intercepts. The second one, doesn't have x-intercepts. You can draw it using transformations. Reflect the parabola over the x-axis and shift it down 8.|dw:1443290058687:dw|
Ooh I see yes that's clever!
:) You can solve this algebraically as well \((x-2)(x+2)(x+2)=-x^2-8\) \((x^2-4)(x+2)=-x^2-8\) \(x^3+2x^2-4x-8=-x^2-8\) \(x^3+3x^2-4x=0\)
Okay thankyo uvery much
you're welcome

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