anonymous
  • anonymous
Did I do this right? Rewrite f(x)=-3(x+2)^2+4 in standard form. f(x)=-3(x+2)(x+2)+4 f(x)=-3(x^2+2x+2x+4)+4 f(x)=-3(x^2+4x+4)+4 f(x)=(3x^2-12x+-12)+4 f(x)=-3^2-12x+-12+4 f(x)=-3x^2+12x-8 Answer is f(x)=-3^2+12x-8 did I do this right or can you tell me where i went wrong?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Nnesha
  • Nnesha
check 4th and last line there are sign mistakes
anonymous
  • anonymous
but the end answer is right except for the sign errors? @Nnesha
Nnesha
  • Nnesha
no the answer isn't correct sign \(\huge\rm \color{red}{erro.Orr}\)

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Nnesha
  • Nnesha
|dw:1443295691039:dw|
Nnesha
  • Nnesha
-3 times x^2 = ?
anonymous
  • anonymous
I redid my work and got \[f(x)=-3x^2-12x-16\]
Nnesha
  • Nnesha
looks good
Nnesha
  • Nnesha
oh hwait no
Nnesha
  • Nnesha
how did you get -16? like i said before there are just sign mistakes
anonymous
  • anonymous
at the end i had -12+4 ?
Nnesha
  • Nnesha
yes right so -12+4 = ?
anonymous
  • anonymous
so \[f(x)=-3x^2-12x-8\] is right?
Nnesha
  • Nnesha
|dw:1443299023462:dw| yes right you forgot the negative at the end so it's -12
Nnesha
  • Nnesha
i meant to say -12x not +12x so yes right the answer uposted in last comment is correct

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