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anonymous

  • one year ago

Did I do this right? Rewrite f(x)=-3(x+2)^2+4 in standard form. f(x)=-3(x+2)(x+2)+4 f(x)=-3(x^2+2x+2x+4)+4 f(x)=-3(x^2+4x+4)+4 f(x)=(3x^2-12x+-12)+4 f(x)=-3^2-12x+-12+4 f(x)=-3x^2+12x-8 Answer is f(x)=-3^2+12x-8 did I do this right or can you tell me where i went wrong?

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  1. Nnesha
    • one year ago
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    check 4th and last line there are sign mistakes

  2. anonymous
    • one year ago
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    but the end answer is right except for the sign errors? @Nnesha

  3. Nnesha
    • one year ago
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    no the answer isn't correct sign \(\huge\rm \color{red}{erro.Orr}\)

  4. Nnesha
    • one year ago
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    |dw:1443295691039:dw|

  5. Nnesha
    • one year ago
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    -3 times x^2 = ?

  6. anonymous
    • one year ago
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    I redid my work and got \[f(x)=-3x^2-12x-16\]

  7. Nnesha
    • one year ago
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    looks good

  8. Nnesha
    • one year ago
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    oh hwait no

  9. Nnesha
    • one year ago
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    how did you get -16? like i said before there are just sign mistakes

  10. anonymous
    • one year ago
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    at the end i had -12+4 ?

  11. Nnesha
    • one year ago
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    yes right so -12+4 = ?

  12. anonymous
    • one year ago
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    so \[f(x)=-3x^2-12x-8\] is right?

  13. Nnesha
    • one year ago
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    |dw:1443299023462:dw| yes right you forgot the negative at the end so it's -12

  14. Nnesha
    • one year ago
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    i meant to say -12x not +12x so yes right the answer uposted in last comment is correct

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