Did I do this right? Rewrite f(x)=-3(x+2)^2+4 in standard form. f(x)=-3(x+2)(x+2)+4 f(x)=-3(x^2+2x+2x+4)+4 f(x)=-3(x^2+4x+4)+4 f(x)=(3x^2-12x+-12)+4 f(x)=-3^2-12x+-12+4 f(x)=-3x^2+12x-8 Answer is f(x)=-3^2+12x-8 did I do this right or can you tell me where i went wrong?

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Did I do this right? Rewrite f(x)=-3(x+2)^2+4 in standard form. f(x)=-3(x+2)(x+2)+4 f(x)=-3(x^2+2x+2x+4)+4 f(x)=-3(x^2+4x+4)+4 f(x)=(3x^2-12x+-12)+4 f(x)=-3^2-12x+-12+4 f(x)=-3x^2+12x-8 Answer is f(x)=-3^2+12x-8 did I do this right or can you tell me where i went wrong?

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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check 4th and last line there are sign mistakes
but the end answer is right except for the sign errors? @Nnesha
no the answer isn't correct sign \(\huge\rm \color{red}{erro.Orr}\)

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Other answers:

|dw:1443295691039:dw|
-3 times x^2 = ?
I redid my work and got \[f(x)=-3x^2-12x-16\]
looks good
oh hwait no
how did you get -16? like i said before there are just sign mistakes
at the end i had -12+4 ?
yes right so -12+4 = ?
so \[f(x)=-3x^2-12x-8\] is right?
|dw:1443299023462:dw| yes right you forgot the negative at the end so it's -12
i meant to say -12x not +12x so yes right the answer uposted in last comment is correct

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