Zela101
  • Zela101
Vector Valued Functions: Describe the graph of the equation
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Zela101
  • Zela101
|dw:1443300346520:dw|
Zela101
  • Zela101
@dan815
Zela101
  • Zela101
|dw:1443300596235:dw|

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More answers

dan815
  • dan815
hello
dan815
  • dan815
you can use t as an angle and think about it liek a polar graph
Zela101
  • Zela101
|dw:1443301007077:dw|
dan815
  • dan815
or you can use t as a 3rd dimension and graph it as a 3d plot whatever u like
Zela101
  • Zela101
Was this a correct approach, dan?
dan815
  • dan815
both are good
Zela101
  • Zela101
|dw:1443301167273:dw|
dan815
  • dan815
yes thats right
Zela101
  • Zela101
Alright, thanks! I was making sure of i'm getting the concept before going ahead and begin with the other problems.
dan815
  • dan815
if u want to think in polar also one more thing to note is that
dan815
  • dan815
you are starting with the tangent vectors along this circle then u have the perpendiculars along the circle
dan815
  • dan815
is perpendicular to
dan815
  • dan815
u just have a different sclaring factor on these vectors
Zela101
  • Zela101
I see. Does it also apply in 3d graphs?
dan815
  • dan815
hmm
dan815
  • dan815
it would be a slightly different interprataion if t wasnt seen as the angle
dan815
  • dan815
but r'(t) should still be perpendicular to r(t)
Zela101
  • Zela101
|dw:1443301651054:dw|
dan815
  • dan815
sint r(t) dot r'(t) = 0 no matter how u plot this
dan815
  • dan815
since*
dan815
  • dan815
not all r(t) dot r'|(t) = 0 ofcourse though
dan815
  • dan815
|dw:1443301819148:dw|
dan815
  • dan815
so this would be a plane with that normal direction vector
dan815
  • dan815
its a line or a curve i mean not a plane
Zela101
  • Zela101
|dw:1443302036857:dw|
Zela101
  • Zela101
Thanks Dan!
dan815
  • dan815
close its z=1+3(x/2)
dan815
  • dan815
but ya
dan815
  • dan815
its just that line along the plane y=-3
Zela101
  • Zela101
|dw:1443302189787:dw|
Zela101
  • Zela101
Lol that was a silly mistake I made
dan815
  • dan815
|dw:1443302201369:dw|
dan815
  • dan815
|dw:1443302270988:dw|
dan815
  • dan815
like that on that y=-3 plane we have this line existing
Zela101
  • Zela101
And this line would be z=1+(3/2)x
dan815
  • dan815
yes
dan815
  • dan815
it looks flipped because x is positive when u go left on the planed noe
Zela101
  • Zela101
Thanks again :)

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