I have my answer, just want to know if the discriminant is right..
y=x^2-5x-8
y=x
2 real solutions and a discriminant of 68.

- anonymous

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- anonymous

Would the discriminant be 68 or 17?

- anonymous

@Hero

- Hero

Would you mind showing your work ?

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## More answers

- anonymous

Yeah one second. I used the quadratic formula -b+-sqrt b^2 - 4ac/2a

- Hero

Do you know what kind of problem this is you're working on?

- anonymous

Yes. I just want to know if my answer is correct

- anonymous

It says "use the discriminant to find the number of solutions for each system."

- freckles

\[\text{ the disciminant of } y=ax^2+bx+c \text{ is } b^2-4ac\]

- anonymous

I know

- freckles

then how did you get two solutions?

- freckles

discriminant will only be one number

- anonymous

Because the answer it gives me is 6+-sqrt68/2 so I was wondering if the discriminant would be 68 or 17 once you simplify it.

- freckles

so you didn't use the formula I wrote...

- anonymous

I did!!

- freckles

b^2-4ac is going to give you the discriminant

- freckles

then how did you get + or - for the discriminant ?

- anonymous

So it would be 68

- freckles

D=b^2-4ac
and you have
a=1
b=-5
c=-8
just plug in
D=(-5)^2-4(1)(-8)
this shouldn't give you 68

- anonymous

Yes it should. You set the two equations equal to each other and get x^2-6x-8=0

- freckles

I see y=x^2-5x-8

- anonymous

Why?

- anonymous

Yes, but there is also the y=x

- freckles

because I thought the question was find the discriminant of y=x^2-5x-8? Is that not the question?

- anonymous

So once you put them equal to each other

- anonymous

Read the entire thing. It is a system. You know with the little {

- anonymous

{y=x^2-5x-8
{y=x

- freckles

Oh I think you are trying to see how many solutions to the system there are
I didn't understand the question because the question wasn't actually given in the title

- anonymous

Yes....

- anonymous

I just wanted to know if the 68 would give me 2 real solutions

- anonymous

Is all I was asking

- freckles

Yes replace y with x in the first equation
\[x=x^2-5x-8 \\ 0=x^2-6x-8 \\ a=1\\ b=-6 \\ c=-8 \\ D=b^2-4ac=(-6)^2-4(1)(-8)=36+32=68>0\]
yes 68>0 so that means you have two solutions

- anonymous

Thank you!

- anonymous

Is what I was saying all along, but... :/

- freckles

It might be good to post the full question in the title next time. It would be very helpful.

- anonymous

Alright, alright.. Thank you nontheless

- freckles

Like determine the number of solutions to the system :p

- anonymous

*nonetheless

- freckles

and np

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