calculusxy
  • calculusxy
MEDAL!!!
Mathematics
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calculusxy
  • calculusxy
MEDAL!!!
Mathematics
katieb
  • katieb
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calculusxy
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freckles
  • freckles
speed=distance/time
freckles
  • freckles
you are given the distance and you are given the amount of time
calculusxy
  • calculusxy
so would i have time be 4 1/3 hr?
freckles
  • freckles
\[20 \text{ minutes}=20 \text{minutes} \cdot \frac{1 \text{ hour }}{60 \text{ minutes}}=\frac{20}{60} \text{ hours }=\frac{1}{3} \text{ hours } \\ \text{ so you have she drove } 500 \text{ km } \text{ in } 4 \frac{1}{3} \text{hours }\] so you time thing is right you might consider it better to write as an improper fraction though
freckles
  • freckles
\[4 \frac{1}{3} \text{ hours}=\frac{13}{3} \text{ hours }\] or I guess a decimal would even work
calculusxy
  • calculusxy
ok i got it its b
freckles
  • freckles
\[\text{ so her speed was } \frac{500 km }{\frac{13}{3} hours }=500 \cdot \frac{3}{13} \frac{ km}{hr} = \frac{1500}{13} \frac{km}{hr}=115.4 \frac{km}{hr}\] yes b is the closest one
freckles
  • freckles
I should have put an approximation sign betwoo 1500/13 and 115.4
freckles
  • freckles
\[\text{ so her speed was } \frac{500 km }{\frac{13}{3} hours }=500 \cdot \frac{3}{13} \frac{ km}{hr} = \frac{1500}{13} \frac{km}{hr} \approx115.4 \frac{km}{hr}\]

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