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hpfan101

  • one year ago

Let f(x)=1/x and g(x)=1/x^2 a) Find f(g(x)) b) Is f(g(x)) continuous everywhere? Explain.

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  1. anonymous
    • one year ago
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    f(x) this is the first function, the x value in this function will be g(x) this means that g(x) will be the input value for f(x) |dw:1443305169960:dw|

  2. hpfan101
    • one year ago
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    Ok so we would get f(g(x))=1/(1/x^2)

  3. hpfan101
    • one year ago
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    Then would it be \[1\times \frac{ x^2 }{ 1 }\]

  4. hpfan101
    • one year ago
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    So f(g(x)= x^2

  5. hpfan101
    • one year ago
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    Ok, I finished solving the question, thanks for the help!

  6. anonymous
    • one year ago
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    The second part to the question is not so simple, though.

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