## A community for students. Sign up today

Here's the question you clicked on:

## anonymous one year ago What is 36x^2-51x+18 factored?

• This Question is Closed
1. campbell_st

start by factoring out 3 $3[12x^2 - 17x + 6]$ so looking at the quadratic... a never fail method for $ax^2 + bx + c$ is to multiply a and c so you have $12 \times 6 = 72$ find the factors of 72 that add to -17... both factors are negative. any thoughts on the factors...?

2. anonymous

3(3x−2)(4x−3)

3. campbell_st

there you go, someone always gives the answer... why not show your working...

4. anonymous

Factors are -9 &-8

5. campbell_st

so then the expression is written as (ax + factor 1)(ax + factor 2) ------------------------- a so your problem becomes $3 \times \frac{(12x -9)(12x -8)}{12}$ now remove the common factors from the binomials $3 \times \frac{4(3x -2)3(4x - 3)}{12}$ then cancel the common factors leaving the answer posted above.. works every time a difficult quadratic can be factored...

#### Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy