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hpfan101
 one year ago
Suppose f is continuous on [1,5] and the only solutions of the equation f(x)=6 are x=1 and x=4. If f(2)=8, explain why f(3)>6.
hpfan101
 one year ago
Suppose f is continuous on [1,5] and the only solutions of the equation f(x)=6 are x=1 and x=4. If f(2)=8, explain why f(3)>6.

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amistre64
 one year ago
Best ResponseYou've already chosen the best response.1spose we have the same setup, only it is lowered by 6 f(1) = 0, f(4) = 0, f(2) = 2 what does that leave for f(3)? why is f(3)>0 ?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1think of the intermediate thrm, or whatever it is called ....

hpfan101
 one year ago
Best ResponseYou've already chosen the best response.0f(3) would be greater than 0 because f(1) and f(4) are equal to 0. So f(3) would have to be values between that to satisfy the intermediate value theorem.

hpfan101
 one year ago
Best ResponseYou've already chosen the best response.0Well, that's what I understood from that theorem.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1yes, f is continuous, and since it has no other f(c)=0 between 1 and 4, then there is noplace or it to cross over at.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1dw:1443306445428:dw

hpfan101
 one year ago
Best ResponseYou've already chosen the best response.0Oh, ok. I understand. Thank you!
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