anonymous
  • anonymous
Calculate the frequency of radiation with a wavelength of 8973 (symbol following is A with a circle on top)
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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whpalmer4
  • whpalmer4
\[8973{\buildrel _{\circ} \over {\mathrm{A}}} \]is that what the wavelength is? Do you know the definition of the \({\buildrel _{\circ} \over {\mathrm{A}}}\) unit?
whpalmer4
  • whpalmer4
\[1\text{ } {\buildrel _{\circ} \over {\mathrm{A}}} = 10^{-10} \text{ m}\] Frequency and wavelength for electromagnetic waves are related by \[c = f \lambda\] where \(c\) is the speed of light in vacuum, \(2.99792458*10^8\text{ m/s}\) \(f\) is frequency and \(\lambda\) is wavelength in meters
anonymous
  • anonymous
yes that is what I was trying to say, thank you I will get back to you if i have questions

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anonymous
  • anonymous
so the wavelength would be : 8973*10^-10?
whpalmer4
  • whpalmer4
yes, wavelength is \(8973*10^{-10}\text{m}\) that gives you \[c = f \lambda\]\[\lambda = \frac{c}{f} = \frac{2.99792458*10^8\text{ m/s}}{8973*10^{-10}\text{m}} =\]
anonymous
  • anonymous
0.000003341 would that be 3.3*10^14 Hz?
whpalmer4
  • whpalmer4
I would carry 4 decimal places to match the 4 you had for the wavelength, but yes, \[3.341*10^{14} \text{ Hz}\]
anonymous
  • anonymous
okay thank you so much, this helped a lot!!
whpalmer4
  • whpalmer4
glad to hear it!

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