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anonymous

  • one year ago

Calculate the frequency of radiation with a wavelength of 8973 (symbol following is A with a circle on top)

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  1. whpalmer4
    • one year ago
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    \[8973{\buildrel _{\circ} \over {\mathrm{A}}} \]is that what the wavelength is? Do you know the definition of the \({\buildrel _{\circ} \over {\mathrm{A}}}\) unit?

  2. whpalmer4
    • one year ago
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    \[1\text{ } {\buildrel _{\circ} \over {\mathrm{A}}} = 10^{-10} \text{ m}\] Frequency and wavelength for electromagnetic waves are related by \[c = f \lambda\] where \(c\) is the speed of light in vacuum, \(2.99792458*10^8\text{ m/s}\) \(f\) is frequency and \(\lambda\) is wavelength in meters

  3. anonymous
    • one year ago
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    yes that is what I was trying to say, thank you I will get back to you if i have questions

  4. anonymous
    • one year ago
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    so the wavelength would be : 8973*10^-10?

  5. whpalmer4
    • one year ago
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    yes, wavelength is \(8973*10^{-10}\text{m}\) that gives you \[c = f \lambda\]\[\lambda = \frac{c}{f} = \frac{2.99792458*10^8\text{ m/s}}{8973*10^{-10}\text{m}} =\]

  6. anonymous
    • one year ago
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    0.000003341 would that be 3.3*10^14 Hz?

  7. whpalmer4
    • one year ago
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    I would carry 4 decimal places to match the 4 you had for the wavelength, but yes, \[3.341*10^{14} \text{ Hz}\]

  8. anonymous
    • one year ago
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    okay thank you so much, this helped a lot!!

  9. whpalmer4
    • one year ago
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    glad to hear it!

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