A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
FIND THE VALUE OF X
anonymous
 one year ago
FIND THE VALUE OF X

This Question is Closed

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Hmm, I'm not very sure, as I'm not so good at geometry, and I don't want to mislead you, sorry.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay thanks could you try another problem? is there anyone else who could help me?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0@phi is good at these kinds of problems

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2you could try \[\frac{2x}{15}=\frac{x+2}{12.5}\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2start with \[12.5\times 2x=15(x+2)\] and solve for \(x\)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Ah, so this one requires a ratio to, like your last question, thanks @misty1212

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2\[\color\magenta\heartsuit\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hold on im sloving it

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Nope, you may have messed up somewhere, \[(12.5)(2x)=15x+30\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Yup, one more step

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok thanks! i need help with a few more!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.