## anonymous one year ago find domain of f(x)= \frac{\sqrt{1 + x}}{9 - x}

$f \left( x \right)=\frac{ \sqrt{1+x} }{ 9-x }$ for domain $x+1\ge0,x \ge -1$ $9-x \neq 0,9 \neq x~or x \neq 9$ domain is [-1,9) U (9, infinity )