anonymous
  • anonymous
what is the solution of x+y=7 2x-4y=8
Mathematics
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anonymous
  • anonymous
what is the solution of x+y=7 2x-4y=8
Mathematics
chestercat
  • chestercat
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jim_thompson5910
  • jim_thompson5910
we have a `y` in the first equation and a `-4y` in the second equation adding them up gives: `y+(-4y) = -3y` which isn't 0 like we want however we can change that `y` to `+4y` by multiplying by 4. Then notice how `4y + (-4y) = 0y = 0`
anonymous
  • anonymous
so it's 0?
jim_thompson5910
  • jim_thompson5910
to change the y to 4y, we have to multiply both sides of the first equation by 4 x+y=7 4*(x+y)=4*7 4x+4y = 28

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jim_thompson5910
  • jim_thompson5910
This system x+y=7 2x-4y=8 turns into 4x+4y=28 2x-4y=8
jim_thompson5910
  • jim_thompson5910
Do you see how to solve 4x+4y=28 2x-4y=8 ??
anonymous
  • anonymous
i don't
anonymous
  • anonymous
would you subtract?
jim_thompson5910
  • jim_thompson5910
you add actually
jim_thompson5910
  • jim_thompson5910
add straight down 4x+4y=28 2x-4y=8 ----------- 6x+0y = 36 so 6x = 36 which means x = ???
anonymous
  • anonymous
6
jim_thompson5910
  • jim_thompson5910
yes
jim_thompson5910
  • jim_thompson5910
now take that x value and plug it into any equation that has x and y in it
jim_thompson5910
  • jim_thompson5910
then solve for y
anonymous
  • anonymous
12-47=8? am i doing that right?
anonymous
  • anonymous
i mean 12-4y=8
jim_thompson5910
  • jim_thompson5910
yes now solve for y
anonymous
  • anonymous
is y 0?
jim_thompson5910
  • jim_thompson5910
no
jim_thompson5910
  • jim_thompson5910
try again

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