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anonymous
 one year ago
If f(x) is an even function and (6, 8) is one the points on the graph of f(x), which reason explains why (–6, 8) must also be a point on the graph?
Since the function is even, the output of a negative xvalue and its opposite is the same.
Since the function is even, the output of a negative yvalue and its opposite is the same.
The graph has rotational symmetry, so the point will be reflected across the yaxis.
The graph has rotational symmetry, so the point will be rotated 90 degrees about the origin.
anonymous
 one year ago
If f(x) is an even function and (6, 8) is one the points on the graph of f(x), which reason explains why (–6, 8) must also be a point on the graph? Since the function is even, the output of a negative xvalue and its opposite is the same. Since the function is even, the output of a negative yvalue and its opposite is the same. The graph has rotational symmetry, so the point will be reflected across the yaxis. The graph has rotational symmetry, so the point will be rotated 90 degrees about the origin.

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