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vera_ewing

  • one year ago

Math question

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  1. vera_ewing
    • one year ago
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  2. jim_thompson5910
    • one year ago
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    They want you to multiply 3 by that matrix

  3. jim_thompson5910
    • one year ago
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    Multiply the 3 by each term inside the matrix \[\large \color{red}{3*}\left[\begin{array}{cccc} -1 & 5 & 5 & -2\\ 2 & 5 & 3 & -4 \end{array}\right] = \left[\begin{array}{cccc} \color{red}{3*}(-1) & \color{red}{3*}5 & \color{red}{3*}5 & \color{red}{3*}(-2)\\ \color{red}{3*}2 & \color{red}{3*}5 & \color{red}{3*}3 & \color{red}{3*}(-4) \end{array}\right] =??\] Note: the final result will be a 2x4 matrix

  4. vera_ewing
    • one year ago
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    -3, 15, 15, -6 6, 15, 15, -12

  5. jim_thompson5910
    • one year ago
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    very good

  6. jim_thompson5910
    • one year ago
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    the first column -1, 2 turns into -3, 6 so it's the same as multiplying the point (-1,2) by 3 to get (-3,6). Dilating it out 3 times further away from the origin

  7. vera_ewing
    • one year ago
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    Ok, so how can I tell which graph it is?

  8. jim_thompson5910
    • one year ago
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    each column of the matrix represents a point or ordered pair

  9. jim_thompson5910
    • one year ago
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    eg: first column -1,2 means we have the point (-1,2)

  10. jim_thompson5910
    • one year ago
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    well I can't see your answer choices

  11. vera_ewing
    • one year ago
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    A.

  12. vera_ewing
    • one year ago
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    B.

  13. vera_ewing
    • one year ago
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    C.

  14. vera_ewing
    • one year ago
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    D.

  15. vera_ewing
    • one year ago
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    @jim_thompson5910 It's A?

  16. jim_thompson5910
    • one year ago
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    one moment

  17. jim_thompson5910
    • one year ago
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    Probably the best thing you can do is just graph each point. What I did was graph using geogebra. That program has a lot of interactivity and flexibility, which is why I like it So you'd graph each column as its own point eg: W = (-1,2), X = (5,5), Y = (5,3), etc etc see the attached as for what you'd get in the graph

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  18. vera_ewing
    • one year ago
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    Thanks so much!

  19. jim_thompson5910
    • one year ago
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    no problem

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