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Wondermath

  • one year ago

Suppose that in a certain population of married couples, 30% of the husbands smoke, 20% of the wives smoke, and in 8% of the couples both the husband and the wife smoke. The question is: For a randomly chosen couple, the husband does not smoke. What is the probability that the wife also does not smoke? ^For this, I need to find the percentage of couples where neither the husband nor the wife smokes. Could somebody show me how to go about doing that? Thanks!

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  1. Vocaloid
    • one year ago
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    venn diagram should be useful here|dw:1443322112659:dw|

  2. Vocaloid
    • one year ago
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    H only + 0.08 = 0.30 W only + 0.08 = 0.20 H only + W only + 0.08 + Neither = 1 solve for "Neither"

  3. Wondermath
    • one year ago
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    Thank you!! I got it :)

  4. Vocaloid
    • one year ago
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    ok, do you know how to finish up the rest of the problem?

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